User ronggang - MathOverflowmost recent 30 from http://mathoverflow.net2013-05-20T19:17:22Zhttp://mathoverflow.net/feeds/user/11056http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/128516/arithmetic-group-over-function-fields-and-its-fundamental-domainarithmetic group over function fields and its fundamental domainronggang2013-04-23T18:21:29Z2013-04-23T21:19:42Z
<p>Let $G$ be a semi-simple algebraic group defined over a global function field $K$.
Let $S$ be a finite set of places of $K$. For a place $v$ of $K$ let $K_v$ be the completion under $v$. We take $K_S=\prod_{v\in S}K_v$ and $O={x\in K: x \mbox{ is integral in }K_v \mbox{ if } v\not \in S }$. It is well known that $G(O)$ is a lattice in $G(K_S)$. Are there any fundamental domain of $G(O)$ expressed in terms of Ziegel sets?</p>
<p>More precisely we want the following type result. If $H$ is semi-simple $\mathbb Q$-group, then it is proved in Theorem 15.5 of Borel's book "Introduction aux groupes arithmétic" that there exists a Ziegel set $F$ and a finite subset
$C\subset G(Q)$ such that $FCG(\mathbb Z)=G(\mathbb R)$. To my understanding this result is not contain in the paper of Borel and Harish-Chandra 1962 on arithmetic groups.</p>
<p>It will be great if one can suggest some references (in English) about it. </p>
http://mathoverflow.net/questions/125782/local-field-and-number-fieldlocal field and number fieldronggang2013-03-28T03:07:46Z2013-03-28T07:29:00Z
<p>Let $K$ be a local field (locally compact topological field) of characteristic zero.
Is it true that $K$ is isomorphic to the completion of a number field
under some valuations?
If yes, then how to prove it?</p>
<p>I ask this question since in a paper it is said that
$k_v^*/(k_v^*)^2$ where $k_v$ is the completion of a number field
at some place $v$ has order 1, 2, 4 or 8. From the structure theory
of local fields this order argument is incorrect for general local fields
of characteristic zero. </p>
<p>If not every local field of characteristic
zero comes from the completion of some number field and the above claim
about the order of $k_v^*/(k_v^*)^2$ is correct.
Can some one prove it or give a reference for it?</p>
http://mathoverflow.net/questions/106259/a-question-on-tits-note-reductive-groups-over-local-fieldsa question on TITS' note "Reductive groups over local fields"ronggang2012-09-03T16:50:05Z2013-03-23T03:29:09Z
<p>This note appears in "Proceedings of Symposia in pure mathematics" vol.33 1979 part 1 pp. 26-69.
The question will be about materials on page 31-32. </p>
<p>Let $G$ be a reductive algebraic group (not necessarily connected) defined over a local field $K$.
We fix a maximal $K$-split torus $S$ of $G$ and take N(resp. Z) to be normalizer
(resp. the centralizer) of $S$ in $G$. Let $X_*=Hom_K (Mult, S)$ (Resp. $X^*=Hom_K (S, Mult)$) be the group of cocharacters (resp. characters) of $S$. Let $V=X_*\otimes_{\mathbb Z}\mathbb R$.
We fix a discrete valuation $\omega: K\to (-\infty, \infty]$.
Let $\nu: Z(K)\to V$ be the homomorphism defined by
$$
\chi (\nu (z))=-\omega (\chi (z)) \quad \mbox{for}\ z\in Z(K) \mbox{ and } \chi \in X^*(\mathbb Z).
$$
Let $Z_c$ be the kernel of $\nu$. Then we have a short exact sequence of gorups
$$
0\to Z(K)/Z_c\to N(K)/Z_c\to N(K)/Z(K)\to 0
$$
where $N(K)/Z(K)$ is a finite group.</p>
<p>Then it is claimed that the map $\nu$ induces a group homomorphism $\phi$ from $N$
to the group of affine transformations of $V$ such that for $z\in Z(K)$ and $x\in V$ one has
$\phi(z)x=x+\nu (z) $. </p>
<p>I do not understand in which way this function $\phi$ is defined. </p>
http://mathoverflow.net/questions/89777/how-many-q-forms-of-sl-nr-are-there-for-a-given-q-rankhow many Q-forms of SL_n(R) are there for a given Q-rankronggang2012-02-28T16:42:11Z2013-01-12T11:17:30Z
<p>Let $G$ be a linear algebraic group defined over $\mathbb Q$.
Suppose that $G$ is isomorphic to $SL_n$ over $\mathbb R$.
Suppose the $\mathbb Q$-rank of $G$ is fixed, say $m$.
How many types are there for $G$ up to $\mathbb Q$-isomorphism?
Are they finite especially for $m>2$?</p>
http://mathoverflow.net/questions/105293/proofs-of-ergodicity-of-sl2-z-action-on-r2-without-using-dualityproofs of ergodicity of Sl(2, Z) action on R^2 without using dualityronggang2012-08-23T03:18:09Z2012-10-03T19:50:42Z
<p>The group $
G=SL(2, R)$ acts linearly on $\mathbb R^2$. The Lebesgue measure of $\mathbb R^2$ is invariant and ergodic for $G$. There is a proof using duality theorem:
Let $U$ be the upper triangular unipotent subgroup of $G$ and let $\Gamma=SL(2, \mathbb Z)$. Then $U$ acts ergodically on $G/\Gamma$. Therefore duality tells us that $\Gamma$ acts ergodically on $G/U\cong \mathbb R^2\backslash 0$.</p>
<p>This method is good but it can not be extended to the group action on non homogeneous manifolds. Are there any other proofs? It is better that I can see different proofs to learn methods.</p>
http://mathoverflow.net/questions/101157/the-group-g-of-algebraic-groups-over-local-fieldsThe group G^+ of algebraic groups over local fieldsronggang2012-07-02T16:24:16Z2012-07-03T08:59:42Z
<p>Let $G$ be an algebraic group defined over a char 0
local field $k$. Following Borel and Tits (73) we define
the group $G^+(k)$ or $G^+$ by the subgroup of $G(k)$
generated by the unipotent elements of $G(k)$. </p>
<p>Suppose $G$ is generated by a finite set of unipotent
$k$-subgroups, say $U_1,\cdots, U_n$. Is it true that
the group generated by $U_1(k), \cdots, U_n(k)$ is
$G^+$? </p>
<p>I feel the answer is positive but do not know how to prove it.
It seems that the ideas of the original paper of Borel and Tits can
help, but I still do not read French (which I always plan to learn) yet. </p>
http://mathoverflow.net/questions/100847/surjectivity-of-rational-points-induced-by-surjective-map-from-affine-spacesurjectivity of rational points induced by surjective map from affine spaceronggang2012-06-28T07:07:04Z2012-06-28T08:22:23Z
<p>Let $k$ be a local field of char $0$ (which is the case I concern).
Let $V$ be a variety defined over $k$ and
let $f: \mathbb A^n\to V$ be a surjective map
(over the algebraic closure of $k$) defined over $k$.
Is it true that the restriction of $f$ to $k$ rational points
$k^n\to V(k)$ surjective?</p>
<p>After it is answered I realized that I simplified what
I want to know too much. Please see the comments for the answer
for more information.</p>
http://mathoverflow.net/questions/97840/is-the-image-of-the-representation-of-the-fundamental-group-associated-to-a-localIs the image of the representation of the fundamental group associated to a local system discrete?ronggang2012-05-24T14:41:28Z2012-05-25T11:23:50Z
<p>If $f: X \to S$ is a projective smooth morphism between complex algebraic varieties. Does the $\pi_1(S)$-representation corresponding to the local system $R^i f_* (C_X)$ on $S$ maps $\pi_1(S)$ onto a discrete subgroup of $GL(r, C)$?</p>
http://mathoverflow.net/questions/49810/unitary-representation-of-semisimple-lie-groups-in-view-of-moores-ergodicity-thmunitary representation of semisimple lie groups in view of Moore's ergodicity thmronggang2010-12-18T15:39:33Z2011-08-27T06:31:52Z
<p>Let $G=G_1\times\ldots\times G_n$ be a product of (connected) simple Lie groups and $(H, \pi)$ be a unitary representation of $G$. In a proof of Moore's ergodicity thm it uses the following fact $$\pi=\oplus_{I\subset [1,\ldots, n]} \pi_I
$$
where $(\pi_I, H_I)$ be the subrepresentation of $\pi$ whose kernel contains
$G_i$ for $i\in I$ but no $G_j$ for $j\not \in I$.</p>
<p>How do we prove this fact?</p>
http://mathoverflow.net/questions/63765/unipotent-group-and-translation-invariant-metricunipotent group and translation invariant metricronggang2011-05-03T02:44:07Z2011-05-03T15:13:13Z
<p>Let $U$ be a unipotent upper triangluar group over a local field $K$ of characteristic
zero. Can we guarantee that there is a right translation invariant metric on $U$ such
that any ball of finite radius is relatively compact?</p>
http://mathoverflow.net/questions/47202/is-the-subgroup-generated-by-one-parameter-unipotent-subgroups-a-lie-subgroupis the subgroup generated by one-parameter unipotent subgroups a Lie subgroup?ronggang2010-11-24T06:04:21Z2011-03-31T12:35:15Z
<p>Let $G$ be a Lie group and $H$ be a subgroup generated by some
one parameter unipotent subgroups (in group sense). Is it true that
$H$ has a Lie group structure which makes it a Lie subgroup of $G$?
Is $H$ closed? </p>
<p>How about for general subgroups?</p>
http://mathoverflow.net/questions/56713/is-restriction-of-scalars-of-simply-connected-algebraic-groups-still-scIs restriction of scalars of simply connected algebraic groups still SC?ronggang2011-02-26T06:47:13Z2011-02-26T07:15:27Z
<p>Let $G$ be a simply connected semisimple algebraic $K$-group and $K$ be a finite extension of $k$.
Is $R_{K/k}G$ still a simply connected algebraic group?</p>
<p>We say $G$ is simply connected if for any central isogeny $G'\to G$ is in fact an isomorphism of algebraic groups. </p>
http://mathoverflow.net/questions/50541/quotient-sigma-algebra-on-quotient-space-of-locally-compact-groupsquotient sigma-algebra on quotient space of locally compact groupsronggang2010-12-28T05:40:51Z2010-12-28T12:39:26Z
<p>Let $G$ be a locally compact second countable topological group and $H$ be a closed subgroup of $G$.
Let $\pi: G\to G/H$ be the quotient map. For the Borel $\sigma$-algebra $\mathcal A$ on $G/H$. Is it true
that $\pi^{-1}(\mathcal A)$ is the Borel subsets of $G$ consisting of right $H$ orbits?</p>
http://mathoverflow.net/questions/49702/is-a-subset-that-contains-no-positive-measurable-subsets-contained-in-a-null-measIs a subset that contains no positive measurable subsets contained in a null measurable set?ronggang2010-12-17T03:27:59Z2010-12-18T19:22:16Z
<p>Let $(X, \mathcal B, \mu)$ be a "good" measure space, e.g. $\mu$ is a positive Radon measure on a locally compact topological space $X$ with Borel $\sigma$-algebra $\mathcal B$. Let $A\subset X$ such that every measurable subset of $A$ has zero measure. Is it true that there is a zero measure set $B$ such that $A\subset B$?</p>
http://mathoverflow.net/questions/47800/is-every-ball-in-a-lie-group-relatively-compactIs every ball in a Lie group relatively compact?ronggang2010-11-30T15:22:34Z2010-11-30T15:33:09Z
<p>Let $G$ be a connected Lie group with a left invariant Riemannian metric which induces a metric $d$ on $G$. Does the ball $B_r$ centered at the identity have compact closure? </p>
<p>It is true in easy examples and looks correct. </p>
http://mathoverflow.net/questions/125782/local-field-and-number-field/125790#125790Comment by ronggangronggang2013-03-28T08:28:36Z2013-03-28T08:28:36ZI see. Thank you.http://mathoverflow.net/questions/125782/local-field-and-number-fieldComment by ronggangronggang2013-03-28T08:24:07Z2013-03-28T08:24:07ZKrasner's Lemma can be used to prove that every local field of characteristic zero comes from completion of a number field.
Therefore it answers the question.http://mathoverflow.net/questions/125782/local-field-and-number-field/125790#125790Comment by ronggangronggang2013-03-28T07:32:09Z2013-03-28T07:32:09ZIt is known that a local field of characteristic zero is a finite extension of $Q_2$. This why I said that $K*/(K^*)^2$ has order 1,2,4 or 8 is incorrect.
The question is whether the order argument is true for local fields
coming from completions of number field? If every local field comes from the completion of a number field, then of course the order argument is incorrect. http://mathoverflow.net/questions/101157/the-group-g-of-algebraic-groups-over-local-fields/101177#101177Comment by ronggangronggang2012-07-03T02:24:35Z2012-07-03T02:24:35Z@Jim: The question is motivated by the p-adic vertion of Rater's Theorem (Margulis Tomanov 94 Invariant measures for actions of unipotent groups over local fields on homogeneous spaces.) They proved the theorem for rational points of unipotent groups, then as a consequence said that the result is also true for groups generated by
rational points of unipotent groups. The question arises from my
attempt to understand arguments between Theorem 1 and 2 of that paper.http://mathoverflow.net/questions/100847/surjectivity-of-rational-points-induced-by-surjective-map-from-affine-space/100848#100848Comment by ronggangronggang2012-06-29T01:39:26Z2012-06-29T01:39:26Z@ Will: It is not surjective even in this case since in general $V^+$ or $V(k)^+$ is not equal to $V(k)$. e.g. PGL_2.http://mathoverflow.net/questions/100847/surjectivity-of-rational-points-induced-by-surjective-map-from-affine-space/100848#100848Comment by ronggangronggang2012-06-28T14:33:33Z2012-06-28T14:33:33ZI mean the group generated by the set $f(k^n)$ has finite index in
the group $V(k)$. Here is the main example in my mind. Suppose $V$ is generated by connected unipotent groups defined over $k$. Then we get such a map $f$ according to I Porp. 2.2 of Borel's algebraic groups.
Then the question is whether the group generated by $k$ points of these unipotent groups has finite index in $V(k)$. If $V$ is semisimple then the question is whether the group they generate contains $V^+$ in the sense of 1973 paper of Borel and Tits(
Homomorphismes "Abstraits" de Groupes Algebriques Simples).
http://mathoverflow.net/questions/100847/surjectivity-of-rational-points-induced-by-surjective-map-from-affine-space/100848#100848Comment by ronggangronggang2012-06-28T08:24:51Z2012-06-28T08:24:51ZSorry, finite index in $V(k)$.http://mathoverflow.net/questions/100847/surjectivity-of-rational-points-induced-by-surjective-map-from-affine-space/100848#100848Comment by ronggangronggang2012-06-28T08:20:28Z2012-06-28T08:20:28ZThanks. In fact what I want to know is the following:
Assume in addition that $V$ is a linear algebraic group.
Is it true that the group generated by $f(k^n)$ has finite
index in $V$?http://mathoverflow.net/questions/56713/is-restriction-of-scalars-of-simply-connected-algebraic-groups-still-scComment by ronggangronggang2011-02-26T14:06:21Z2011-02-26T14:06:21ZI think I would assume $K/k$ is separable. Are there any convenient reference for this full weight lattice characterization?http://mathoverflow.net/questions/49810/unitary-representation-of-semisimple-lie-groups-in-view-of-moores-ergodicity-thmComment by ronggangronggang2010-12-19T01:33:17Z2010-12-19T01:33:17ZI think I should give a ref. for this.
Ergodic theory and topological dynamics of group actions on homogeneous spaces, M Bekka & M Mayer, Cambridge University Press, P91.
In fact, I don't quite believe this fact.http://mathoverflow.net/questions/47800/is-every-ball-in-a-lie-group-relatively-compactComment by ronggangronggang2010-12-01T12:21:24Z2010-12-01T12:21:24ZAccording to Hopf-Rinow, one needs to show the space is complete. This follows from the fact that the metric is left invariant, and it is complete locally!http://mathoverflow.net/questions/47800/is-every-ball-in-a-lie-group-relatively-compactComment by ronggangronggang2010-12-01T00:22:29Z2010-12-01T00:22:29ZThanks, Igor!!!!http://mathoverflow.net/questions/47202/is-the-subgroup-generated-by-one-parameter-unipotent-subgroups-a-lie-subgroup/47263#47263Comment by ronggangronggang2010-11-29T02:12:59Z2010-11-29T02:12:59ZAnother correction: The above is true in case of two parabolic $k$-subgroups containing a common minimal parabolic $k$-subgroup of ...........;http://mathoverflow.net/questions/47202/is-the-subgroup-generated-by-one-parameter-unipotent-subgroups-a-lie-subgroup/47263#47263Comment by ronggangronggang2010-11-29T02:11:18Z2010-11-29T02:11:18ZA correction:
$(M_1M_2)(k)=M_1(k)M_2(k)$http://mathoverflow.net/questions/47202/is-the-subgroup-generated-by-one-parameter-unipotent-subgroups-a-lie-subgroup/47263#47263Comment by ronggangronggang2010-11-29T02:10:07Z2010-11-29T02:10:07ZDear Zroslav: This theorem only holds for the rational points over an algebraically closed field. It seems not true that $(M_1M_2)(k)=(M_1M_2)(k)$ which is true in some special cases, e.g. two parabolic
$k$-subgroups of a connected reductive $k$-group.