Koszulness of the cohomology ring of moduli of stable genus zero curves

2012-06-14T14:47:47Z

Let $n \geq 3$. The ring $H^\bullet(\overline{M}_{0,n},\mathbf Q)$ was determined by Sean Keel. It is generated by the cohomology classes of boundary divisors $D_{A,B}$ corresponding to partitions $A \sqcup B = \{1,\ldots,n\}$ of the marked points with $|A|, |B| \geq 2$, and where $D_{A,B} = D_{B,A}$. All relations are given by: (i) demanding that the product $D_{A,B} \cdot D_{A',B'}$ vanishes if the two divisors are disjoint (i.e. if there are no containments between the four sets $A,A',B$ and $B'$); (ii) the relation $$ \sum_{\substack{\{i,j\} \subseteq A \\ \{k,l\} \subseteq B}} D_{A,B} = \sum_{\substack{\{i,k\} \subseteq A \\ \{j,l\} \subseteq B}} D_{A,B} $$ which follows by pulling back the WDVV relation on $\overline{M}_{0,4}$ to $\overline M_{0,n}$ .

It follows in particular that $H^{2\bullet}(\overline{M}_{0,n},\mathbf Q)$ is a quadratic algebra. I was asked during a seminar today whether this algebra is Koszul, but I had no idea what to answer. So, is it Koszul? If so, is its Koszul dual interesting?

Answer by Neil Strickland for Koszulness of the cohomology ring of moduli of stable genus zero curves

2012-06-15T17:17:56Z

Here is an alternative presentation of the cohomology, taken from the unpublished PhD thesis of my student Daniel Singh. It has the disadvantage that one marked point is treated specially, so some symmetry is lost, but otherwise has many pleasant properties.

Put $S=\{1,\dotsc,n-1\}$ .

For each subset $T\subseteq S$ with $|T|>1$ we have a generator $x_T$ in degree two.
For each pair of sets $T,U$ with $T\cap U\neq\emptyset$ we have $(x_{T\cup U}-x_T)(x_{T\cup U}-x_U)=0$.
Now consider a set $T$ as before, and disjoint subsets $U_1,\dotsc,U_r\subseteq T$, again with $|U_i|>1$. Put $m=(|T|-1)-\sum_i(|U_i|-1)$. Then $x_T^m\prod_i(x_T-x_{U_i})=0$.
Moreover, there are no more generators or relations.

One can also give a basis for the cohomology consisting of monomials in the generators $x_T$.

Consider a monomial $y=\prod_Tx_T^{n_T}$. The shape of $y$ is $\{T : n_T>0\}$ .
We say that a collection $\mathcal{F}$ of subsets of $S$ is a forest if all elements have size at least two, and any two elements are either disjoint or nested.
Given a forest $\mathcal{F}$ and a set $T\in\mathcal{F}$, let $U_1,\dotsc,U_r$ be the maximal elements of $\{V\in\mathcal{F}:V\subset T\}$ , and then put $m(\mathcal{F},T)=(|T|-1)-\sum_i(|U_i|-1)$.
We say that our monomial $y$ is admissible if $\text{shape}(y)$ is a forest and $n_T\lt m(\text{shape}(y),T)$ for all $T\in\text{shape}(y)$.

It can be shown that the admissible monomials form a basis for the cohomology.

I do not know whether the algebra is Koszul, but I think that this presentation is well-adapted for investigating that question.

Koszulness of the cohomology ring of moduli of stable genus zero curves - MathOverflow

Koszulness of the cohomology ring of moduli of stable genus zero curves

Answer by Neil Strickland for Koszulness of the cohomology ring of moduli of stable genus zero curves