When is a topological group Hausdorff (separated)? - MathOverflow most recent 30 from http://mathoverflow.net2013-06-20T05:45:27Zhttp://mathoverflow.net/feeds/question/99478http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/99478/when-is-a-topological-group-hausdorff-separatedWhen is a topological group Hausdorff (separated)?Jérémy Blanc2012-06-13T17:01:46Z2012-06-13T20:02:59Z
<p>Does someone knows a good reference for the following result?</p>
<p>"A topological group is Hausdorff if and only if the identity is closed."</p>
<p>I have seen proofs in lecture notes of courses on the web, but I would like a reference in a book or an article, in order to refer to it.</p>
http://mathoverflow.net/questions/99478/when-is-a-topological-group-hausdorff-separated/99480#99480Answer by Greg Marks for When is a topological group Hausdorff (separated)?Greg Marks2012-06-13T17:31:03Z2012-06-13T17:31:03Z<p>You can probably find this result in a million places, one of which is N. Bourbaki, <i>General Topology</i>, Part 1, Chapter 3, Section 1.2, p. 223, Proposition 2.</p>
http://mathoverflow.net/questions/99478/when-is-a-topological-group-hausdorff-separated/99481#99481Answer by Igor Rivin for When is a topological group Hausdorff (separated)?Igor Rivin2012-06-13T17:35:23Z2012-06-13T17:35:23Z<p>Bourbaki, General Topology, III.2.5, prop 13. This is from an answer to <a href="http://mathoverflow.net/questions/9022/quotient-of-a-hausdorff-topological-group-by-a-closed-subgroup" rel="nofollow">this question</a>.</p>
http://mathoverflow.net/questions/99478/when-is-a-topological-group-hausdorff-separated/99494#99494Answer by AliReza Olfati for When is a topological group Hausdorff (separated)?AliReza Olfati2012-06-13T20:02:59Z2012-06-13T20:02:59Z<p>You could find a routin proof in the book "Topological Ring" written by Seth Warner. In this book at page 21 in Theorem 3.4 you could see the following Proposition:</p>
<p>Theorem: Let $G$ be a topological group. The following statements are equivalent: </p>
<ol>
<li>{$0$} is closed.</li>
<li>{$0$} is an intersection of the neighborhoods of zero. </li>
<li>$G$ is Hausdorff.</li>
<li>$G$ is regular. </li>
</ol>
<hr>
<p>You could also find the improvement of it in the book "<strong>Topology for analysis</strong>" Written by <strong>Albert Wilansky</strong>. In section 12 at page 243 You could see the following theorem:</p>
<p>THEQREM: Every topological group is completely regular. The following conditions on
a topological group $G$ are equivalent: </p>
<ul>
<li>$G$ is a $T_0$ space.</li>
<li>$G$ is a Tychonoff space.-</li>
<li>$\cap${$U:U$ is a is a neighborhood of $e$}={$e$}</li>
</ul>
<p>The Proof of Complete regularity Has more details. I think The proof is in the level of Urysohn Lemma.</p>
<hr>
<p>But if you are interested in the general case, I Suggest You look at the section "uniformity" which were discussed in the following books:</p>
<ul>
<li>Topology for Analysis: Chapter 11</li>
<li>General topology: Stephen Willard: chapter 9 </li>
</ul>