Recognize this plane curve? - MathOverflow most recent 30 from http://mathoverflow.net2013-05-19T06:28:43Zhttp://mathoverflow.net/feeds/question/98482http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/98482/recognize-this-plane-curveRecognize this plane curve?Joseph O'Rourke2012-05-31T13:00:49Z2012-05-31T13:46:28Z
<p>An aspect of my work led to a plane curve with implicit equation
$$
x^2+y^2 = 3 (y/2)^{2/3} + 1
$$
Actually, I started with the parametrization below and derived from it the
equation above:
<code>\begin{eqnarray}
x(t) &=& t (3-2 t^2) \\
y(t) &=& 2(1-t^2)^{3/2}
\end{eqnarray}</code></p>
<p>Here is what it looks like:
<br />
<img src="http://cs.smith.edu/~orourke/MathOverflow/KnightsVisorImplicitEqn.jpg" alt="Plots" />
<br /></p>
<p>If this falls in some classical class of curves, and perhaps even has a name,
I would like to reference it appropriately.
Does anyone recognize this curve?
Thanks!</p>
<p><b>Answered</b>. By Sylvain Bonnot and Francesco Polizzi: It is a type of <em>nephroid</em>!
Here's the Wikipedia image from the article they both cited:
<br />
<img src="http://upload.wikimedia.org/wikipedia/commons/0/02/EpitrochoidOn2.gif" alt="Wiki image"></p>
http://mathoverflow.net/questions/98482/recognize-this-plane-curve/98483#98483Answer by Sylvain Bonnot for Recognize this plane curve?Sylvain Bonnot2012-05-31T13:20:50Z2012-05-31T13:20:50Z<p>Pretty curve...I think it is a Nephroid:
<a href="http://en.wikipedia.org/wiki/Nephroid" rel="nofollow">http://en.wikipedia.org/wiki/Nephroid</a></p>
http://mathoverflow.net/questions/98482/recognize-this-plane-curve/98484#98484Answer by Francesco Polizzi for Recognize this plane curve?Francesco Polizzi2012-05-31T13:26:21Z2012-05-31T13:26:21Z<p>Your curve is a <em>nephroid</em>, see <a href="http://en.wikipedia.org/wiki/Nephroid" rel="nofollow">http://en.wikipedia.org/wiki/Nephroid</a>.</p>
<p>The general equation of such a plane curve is $$(x^2+y^2-4a^2)^3=108a^4y^2.$$ Your example corresponds to the value $a=\frac{1}{2}$ of the parameter.</p>