Certain functional equations for the Riemann Zeta function? - MathOverflow most recent 30 from http://mathoverflow.net2013-06-19T18:18:34Zhttp://mathoverflow.net/feeds/question/97929http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/97929/certain-functional-equations-for-the-riemann-zeta-functionCertain functional equations for the Riemann Zeta function? Roupam Ghosh2012-05-25T10:15:11Z2012-05-28T15:34:09Z
<p>Referring to <a href="http://math.stackexchange.com/questions/147377/other-functional-equations-for-zetas" rel="nofollow">this</a> question I asked on math.SE.
I am posting a more generalized question here, for answers and further inquiry.</p>
<blockquote>
<p>For the Riemann zeta function, we know of the standard functional equation that relates $\zeta(s)$ and $\zeta(1-s)$. I wanted to know whether there are functional equations that relates $\zeta(s)$ and $\zeta(s+1)$, or $\zeta(s)$, $\zeta(s+1)$, and $\zeta(s+2)$ or in general $\zeta(s)$, $\zeta(s+1)$, $\zeta(s+2)$, ..., $\zeta(s+n)$ for $\Re(s) > 0$ and for $n \in \mathbb{N}$?</p>
</blockquote>
<p><em>My main motivation behind asking this question is I have found such an equation, but I do not know whether such an equation exists in literature. Also, I do not want to appear as if I am promoting my formula here, but rather I am more interested in the works that have been done in such directions.</em></p>
<p><em>My formula goes as follows: For any $n \in \mathbb{N}$ and $\Re(s) > 0$ we have</em>
$$\frac{1}{s-1} + \sum_{r=1}^n \binom{n}{r} (-1)^r \left(\frac{\zeta(s+r-1)}{s+n-1} + \int_1^\infty\frac{\rho(x)^r}{x^{s+r}}\mathrm{d}x\right) = 0$$
<em>where $\binom{n}{r}$ is the binomial coefficient and $\rho(x)$ is the fractional part of $x$</em> </p>
<p><em>For example, putting $n=1$ we get the well known identity,</em>
$$\frac{1}{s-1} - \frac{\zeta(s)}{s} - \int_1^\infty\frac{\rho(x)}{x^{s+1}}\mathrm{d}x = 0$$
<em>putting $n=2$,</em>
$$\frac{1}{s-1} - 2\left(\frac{\zeta(s)}{s+1} + \int_1^\infty\frac{\rho(x)}{x^{s+1}}\mathrm{d}x\right) + \left(\frac{\zeta(s+1)}{s+1} + \int_1^\infty\frac{\rho(x)^2}{x^{s+2}}\mathrm{d}x\right) = 0$$
<em>and so on...</em></p>
<p>EDIT: Classic answer by Juan. This question is now solved.</p>
http://mathoverflow.net/questions/97929/certain-functional-equations-for-the-riemann-zeta-function/98177#98177Answer by juan for Certain functional equations for the Riemann Zeta function? juan2012-05-28T07:45:11Z2012-05-28T14:51:38Z<p>Equations of this type are known. You may see, for example, the classical
book "Primzahlen" by Landau paragraph 67. "Continuation of the zeta function by partial integration"</p>
<p>There it is proved the formula
$$ (s-1)(\zeta(s)-1)-1=-\frac{(s-1)s}{2!}(\zeta(s+1)-1)-
\frac{(s-1)s(s+1)}{3!}(\zeta(s+2)-1)-\cdots$$
$$\cdots-\frac{(s-1)s\cdots(s+q)}{(q+2)!}(\zeta(s+q+1)-1)
-\frac{(s-1)s\cdots(s+q+1)}{(q+2)!}\int_1^\infty \frac{\rho(x)^{q+2}}{x^{s+q+2}} dx.$$</p>
<p>From this we may get the beautiful formula
$$1=\binom{s-1}{1}(\zeta(s)-1)+\binom{s}{2}(\zeta(s+1)-1)+\binom{s+1}{3}(\zeta(s+2)-1)+
\cdots$$
(See Titchmarsh 2.14, formula (2.14.1) and also (2.14.2))</p>
<p>From the formula in Landau you see that the integral
$\int_1^\infty \frac{\rho(x)^r}{x^{s+r}}\,dx$ can be expressed in terms of the
$\zeta(s+k)$. </p>