Orthogonality in non-inner product spaces - MathOverflow most recent 30 from http://mathoverflow.net2013-05-22T10:47:12Zhttp://mathoverflow.net/feeds/question/90129http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/90129/orthogonality-in-non-inner-product-spacesOrthogonality in non-inner product spacesUday2012-03-03T17:47:13Z2012-03-04T11:10:12Z
<p>I have come across a notion of orthogonality of two vectors in a normed space not necessarily inner product space. Two vectors $x$ and $y$ in a normed space are said to be orthogonal (represented $x\perp y$) if $||x||\leq ||x+\alpha y||,$ for every $\alpha,$ a scalar. </p>
<p>1) What is the rational behind the definition above? I guess, it has got something to do with minimum overlap between $x$ and $y$. </p>
<p>2) Is this unique generalization of the concept of orthogonality from inner product spaces?</p>
<p>Thank you. </p>
http://mathoverflow.net/questions/90129/orthogonality-in-non-inner-product-spaces/90136#90136Answer by András Bátkai for Orthogonality in non-inner product spacesAndrás Bátkai2012-03-03T19:24:58Z2012-03-03T19:24:58Z<p>Well, it depends what do you need it for. You may also have a look at <a href="http://en.wikipedia.org/wiki/Semi-inner-product" rel="nofollow">semi-inner-product spaces</a>, which are natural generalizations of inner product spaces.</p>
http://mathoverflow.net/questions/90129/orthogonality-in-non-inner-product-spaces/90140#90140Answer by Ralph for Orthogonality in non-inner product spacesRalph2012-03-03T19:55:09Z2012-03-03T19:55:09Z<p>Concerning question 1: The rational is that in an inner product space $$x\perp y \Leftrightarrow \forall \alpha \in K: ||x||\leq ||x+\alpha y|| \qquad(K = \mathbb{R} \text{ or } K = \mathbb{C})$$
Now, if no inner product is available (but a norm), the idea is, to just take the right hand side as definition of orthogonality (call it $\perp_1$). </p>
<p>Concerning question 2: No, there are other -non-equivalent - generalizations as well. As an example, note that in an inner product space over the reals
$$\langle x,y \rangle = \frac{1}{4}( ||x+y||^2 - ||x-y||^2).$$
Hence $x\perp y \Leftrightarrow ||x+y|| = ||x-y||$. So the definition
$$ x\perp_{\scriptstyle 2}\; y : \Leftrightarrow ||x+y|| = ||x-y||$$
generalizes the orthogonality from an inner product space to any normed space (over the reals).</p>
<p>Now let's show that $\perp_1, \perp_2$ aren't equivalent. Let $E = \mathbb{R}^2$ with norm $||(a,b)|| = \max(|a|, |b|)$. Then </p>
<p>$\qquad (0,1) \perp_2 (2,1)$ but <strong>not</strong> $(0,1) \perp_1 (2,1)\quad$ (take $t=-1/4$)</p>
<p>$\qquad (1,1) \perp_1 (2,0)$ but <strong>not</strong> $(1,1) \perp_2 (2,0).$ </p>
http://mathoverflow.net/questions/90129/orthogonality-in-non-inner-product-spaces/90177#90177Answer by Valerio Capraro for Orthogonality in non-inner product spacesValerio Capraro2012-03-04T03:08:39Z2012-03-04T10:37:57Z<p>The definition you gave is called Birkhoff-James orthogonality and the intuition is the following: suppose you have $x,y\in\mathbb R^2$ and construct a triangle with sides $x$ and $y$. Now let $x$ be fixed and consider the same triangle with $-\alpha y$ instead of $y$. Observe that $||x+\alpha y||$ is the length of the third side of this triangle. If you try to write down a picture, you figure out in a moment that the condition $||x||\leq||x+\alpha y||$ can be true for all $\alpha$ iff $x$ and $y$ are orthogonal (looking at the picture, if they are not orthogonal and the inequality is true for some $\alpha$, then it is false for $-\alpha$). Birkhoff-James' orthogonality is a tentative to capture orthogonality through this geometric property.</p>
<p>Birkhoff-James' orthogonality is not the unique notion of orthogonality for normed space. </p>
<p>Some references:</p>
<p>In the following paper</p>
<p><a href="http://arxiv.org/pdf/0907.1813.pdf" rel="nofollow">http://arxiv.org/pdf/0907.1813.pdf</a></p>
<p>you can find some recent very easy application of BJ's orthogonality, as well, if you go through the bibliography, some references about other notions of orthogonality are given. In particular I suggest the paper of Diminnie </p>
<p>Diminnie, C.R. A new orthogonality relation for normed linear spaces, Math. Nachr. 114 (1983), 192-203</p>
<p>and the survey by Alonso and Benitez
<a href="http://dmle.cindoc.csic.es/pdf/EXTRACTAMATHEMATICAE_1989_04_03_03.pdf" rel="nofollow">http://dmle.cindoc.csic.es/pdf/EXTRACTAMATHEMATICAE_1989_04_03_03.pdf</a></p>
<p>P.s. Bikhoff-James orthogonality is not symmetric in general. Some interesting remarks about symmetric orthogonalities can be found in the paper(s) by Partington in the bibliography of the arxiv paper cited above.</p>
http://mathoverflow.net/questions/90129/orthogonality-in-non-inner-product-spaces/90187#90187Answer by J.J. Green for Orthogonality in non-inner product spacesJ.J. Green2012-03-04T09:58:44Z2012-03-04T11:10:12Z<p>Concerning your follow-up question (iii) there is the following very nice result: For Birkhoff-James orthogonality
it is easy to find examples where $y\perp x$ but
$\left\|x\right\|/\left\|x+\alpha y\right\| > 1$ for some real $\alpha$, and so
natural to investigate the largest such value
$\left\|x\right\|/\left\|x+\alpha y\right\|$ over $X$.
In "R. L. Thele, Some results on the radial projection in Banach spaces.
Proc. Amer. Math. Soc., 42(2):484--486", it is it is shown that this quantity
is exactly the Lipshitz constant for the radial projection onto the unit ball
in this norm. </p>