Expected minimum face angle of random convex polyhedron in $\mathbb{R}^3$ - MathOverflow most recent 30 from http://mathoverflow.net2013-05-24T18:51:24Zhttp://mathoverflow.net/feeds/question/87230http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/87230/expected-minimum-face-angle-of-random-convex-polyhedron-in-mathbbr3Expected minimum face angle of random convex polyhedron in $\mathbb{R}^3$Joseph O'Rourke2012-02-01T14:05:27Z2013-01-29T19:10:51Z
<p>Let $P_n$ be a "random convex polyhedron" in $\mathbb{R}^3$ of $n$ vertices, where "random" could follow any one
of a number of models:
(1) the convex hull of $n$ points randomly and uniformly distributed <em>on</em> a sphere;
(2) the convex hull of $N>n$ points randomly and uniformly distributed <em>in</em> a sphere;
(3) analogous definitions but using different distributions, or replacing "sphere" by "a given convex body."
I think my question is largely independent of the precise model:</p>
<blockquote>
<p>Does the expected measure of the minimum face angle $\theta_{\min}$
over all faces of $P_n$ go to zero
as $n \rightarrow \infty$?</p>
</blockquote>
<p>I am hoping there is a succinct argument that avoids computing the precise expectation
of $\theta_{\min}$, which might be difficult, and would certainly depend on the model.
I have seen many papers on properties of random convex hulls, but none that I've found
address my specific question. Thanks for ideas/pointers, under any model!</p>
http://mathoverflow.net/questions/87230/expected-minimum-face-angle-of-random-convex-polyhedron-in-mathbbr3/87232#87232Answer by Pietro Majer for Expected minimum face angle of random convex polyhedron in $\mathbb{R}^3$Pietro Majer2012-02-01T14:40:52Z2012-02-01T14:55:14Z<p>For i.i.d. points chosen in a bounded subset of $\mathbb{R}^3$ (or $\mathbb{R}^d$) it seems to me that $\theta_\min(n)\to 0$ is ensured when the support of the distribution has a smooth boundary. This covers the case of the uniform distribution on an Euclidean ball, and a uniform spherical distribution as well. (I'm not quite sure about how to state a converse). </p>
http://mathoverflow.net/questions/87230/expected-minimum-face-angle-of-random-convex-polyhedron-in-mathbbr3/87237#87237Answer by Liviu Nicolaescu for Expected minimum face angle of random convex polyhedron in $\mathbb{R}^3$Liviu Nicolaescu2012-02-01T15:13:20Z2012-02-01T15:13:20Z<p>Section 8.2.4 of </p>
<blockquote>
<p>Rolf Schneider, Wolfgang Weil:
Stochastic and Integral Geometry,
Springer Verlag 2008</p>
</blockquote>
<p>may be a good place to start. Roughly, there they select $n$ random points in a given convex body (say the unit ball) and they describe the large $n$ behavior of support function of the expected convex hull. There are lots of references and historical remarks following this subsection and maybe you get lucky.</p>
http://mathoverflow.net/questions/87230/expected-minimum-face-angle-of-random-convex-polyhedron-in-mathbbr3/120246#120246Answer by Günter Rote for Expected minimum face angle of random convex polyhedron in $\mathbb{R}^3$Günter Rote2013-01-29T19:10:51Z2013-01-29T19:10:51Z<p>The answer is YES. (I am assuming you mean the angle between two adjacent edges on a common face. (The dihedral angles all go to $\pi$.)) The easy and brief reason is that, in a large random point set, everything (that depends on <em>local</em> conditions) happens almost surely.</p>
<p>Here is a sketch of a proof for your model (1).</p>
<ol>
<li>Fix $\varepsilon>0$ arbitrarily, and take a (small) triangle $abc$ on the sphere with smallest angle $\varepsilon$.</li>
<li>Construct its circumcircle $K_0$.</li>
<li>Let $K$ be a concentric circle twice as large as $K_0$.</li>
<li>Construct some small neighborhoods $A,B,C$ around $a,b,c$ such that any triangle with vertices taken from these neighborhoods
<ol>
<li>has smallest angle $<2\varepsilon$.</li>
<li>has its circumcircle within $K$.</li>
</ol></li>
<li><p>Now we let the number $n$ of points go to infinity. For each $n$:</p>
<ol>
<li>Construct a scaled-down copy of the configuration $A',B',C',K'$ of $A,B,C,K$ (but still <em>on</em> the sphere) such that the expected number of points that falls into $K'$ is 3. (The area of $K'$ is a $3/n$ fraction of the whole sphere.)</li>
<li>Now, the probability that
exactly 3 points fall into $K'$ is at least some positive probability $p_0$, independend of $n$. ($p_0$ is not so small, the number of points is essentially Poisson-distributed with mean 3.)</li>
<li>The probability that
<blockquote>
<p>one point each falls into $A'$, $B'$, and $C'$ but no other point falls into $K'$ </li>
</ol>
<p>is at least some (small) constant $p_1>0$ (independent of $n$). The reason is that $A'$, $B'$, $C'$ have some (almost) constant fraction of the area of $K'$.</p>
</p>
<ol>
<li>If this event happens, there will be a face angle smaller than $2\varepsilon$.</li>
<li>Now, place const$\cdot n$ disjoint copies $A',B',C',K'$ on the sphere. Then these copies behave essentially like independent Bernoulli experiments with success probability $p_1$. As $n\to\infty$, the probability of having at least one "success" approaches 1.</li>
</ol>
<p></blockquote></p></li>
</ol>