Heegaard splitting of covering hyperbolic manifold. - MathOverflow most recent 30 from http://mathoverflow.net2013-06-19T16:34:48Zhttp://mathoverflow.net/feeds/question/86800http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/86800/heegaard-splitting-of-covering-hyperbolic-manifoldHeegaard splitting of covering hyperbolic manifold.yanqing 2012-01-27T07:27:40Z2012-04-04T02:19:32Z
<p>I am curious about how the Heegaard genus changes after a finite covering. </p>
<p>Is there anyone constructing an closed hyperbolic 3-manifold $N$ such that </p>
<p>the Heegaard genus of a finite covering of $N$ is less than the Heegaard genus of $N$? </p>
<p>Thank you!</p>
<p>Note: Heegaard genus of a 3-manifold means the minimal genus of all Heegaard splittings.</p>
http://mathoverflow.net/questions/86800/heegaard-splitting-of-covering-hyperbolic-manifold/86831#86831Answer by Michael Siler for Heegaard splitting of covering hyperbolic manifold.Michael Siler2012-01-27T15:05:32Z2012-01-27T15:05:32Z<p>There are examples like this. Check out section 4.5 of Shalen's paper "Hyperbolic volume, Heegaard genus and ranks of groups." It's here: <a href="http://arxiv.org/abs/0904.0191" rel="nofollow">http://arxiv.org/abs/0904.0191</a></p>
<p>He gives a reference for a genus 3 example by Alan Reid and a sketch of a technique for producing examples by Hyam Rubinstein. Shalen also conjectures that the genus can drop by at most 1 in a finite cover of a closed hyperbolic 3-manifold.</p>
http://mathoverflow.net/questions/86800/heegaard-splitting-of-covering-hyperbolic-manifold/93062#93062Answer by Yo'av Rieck for Heegaard splitting of covering hyperbolic manifold.Yo'av Rieck2012-04-04T02:19:32Z2012-04-04T02:19:32Z<p>Hyam Rubinstein and me have results about the behavior of the Heegaard genus under double covers for non-Haken manifolds, see <a href="http://arxiv.org/abs/math/0607145" rel="nofollow">http://arxiv.org/abs/math/0607145</a>. Essentially, we show that the Heegaard genera of the two manifolds bound each other linearly. (The statement is a little more complicated for branched covers.)</p>