How to solve simple bilinear equations under extra linear constraints - MathOverflow most recent 30 from http://mathoverflow.net2013-05-20T17:20:37Zhttp://mathoverflow.net/feeds/question/84213http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/84213/how-to-solve-simple-bilinear-equations-under-extra-linear-constraintsHow to solve simple bilinear equations under extra linear constraintsWoland2011-12-24T07:25:28Z2011-12-24T08:04:52Z
<p>Hello,</p>
<p>This is the full version of a question I asked earlier. I am trying to understand whether finding a solution to the following bilinear system is computationally hard or easy:</p>
<p>$\lambda_i^T u_{ij} = 0$ for all $i,j$</p>
<p>$\sum_{i=1}^n u_{ij} = u_j$ for all $j$</p>
<p>$\sum_{j=1}^m (e p_j^T - e^T p_j I)u_{ij} \geq 0$ for all $i$</p>
<p>$\lambda_i \geq 0$ for all $i$</p>
<p>$e^T \lambda_i = 1$ for all $i$</p>
<p>The variables are $\lambda_i$ and $u_{ij}$, the constants are $p_j$ and $u_j$, and $e$ is the vector of all ones. If the dimension of the $\lambda_i,u_{ij}$ is $k$, then the numbers of variables $m,n$ are related by $m=(n-1)^k$.</p>
<p>Is solving this underdetermined bilinear system NP-hard or can one find a solution? Bilinear systems are NP-hard in general, but all proofs I have seen involve manipulating the matrix $A$ in $x^TAy$. I don't understand how extra linear constraints affect the complexity of the bilinear equations.</p>
<p>Thank you in advance!</p>