most recent 30 from http://mathoverflow.net 2013-06-20T11:27:40Z http://mathoverflow.net/feeds/question/82283 http://www.creativecommons.org/licenses/by-nc/2.5/rdf http://mathoverflow.net/questions/82283/not-hard-calculus-exercise steve 2011-11-30T15:50:07Z 2011-11-30T15:55:29Z

<p>If $$ (f \circ g \circ f)(x)=x, \forall x \epsilon \mathbb{R}$$ then show that $$(f \circ g)(x)=( g \circ f)(x)$$</p>