Chain complexes of vector bundles

2011-09-28T07:20:54Z

In his paper "Categories and cohomology theories" Graeme Segal considers the category of finite length chain complexes of finite dimensional vector spaces: Let $n = (n_i)_{i \in \mathbb{Z}}$ be a sequence of positive integers almost all zero. Then he claims that the space $K_n$ of chain complexes $E$ with $E^i = \mathbb{R}^{n_i}$ is a real algebraic variety. I am no algebraic geometer, but I suspect this to be similar to flag varieties somehow. So my first question is:

What is the topology on $K_n$?

As morphisms in the above mentioned category he takes chain homotopy equivalences between these complexes and claims that these also form a topological space. So:

What is the topology on Mor($E,F$) for two chain complexes $E$ and $F$ as described above?

Answer by Jeffrey Giansiracusa for Chain complexes of vector bundles

2011-09-28T07:55:17Z

The space $K_n$ sits inside the space of sequences of linear maps $$L_n = \Pi_i Hom(E^i,E^{i+1}).$$ This is just a space of sequences of matrices, so it is a real vector space of dimension $\sum_i (n_i \cdot n_{i+1})$. We give it the usual euclidean topology for real vector spaces.

The subspace $K_n$ consists of those sequences of linear maps ${f_i}$ which form a chain complex - i.e., $f_{i+1} \circ f_i = 0$. This condition is polynomial in the entries in the matrices, so $K_n$ is a real algebraic affine subvariety inside $L_n$. We give $K_n$ the subspace topology.

The topology on the space of morphism can be described similarly by embedding the morphism set $Mor(E,F)$ into the space of sequences of linear maps $\Pi_i Hom(E^i,F^i)$, which is again a real vector space. The condition of being a morphism of chain complexes is real algebraic so the morphism space is again a real algebraic affine variety.

Chain complexes of vector bundles - MathOverflow

Chain complexes of vector bundles

Answer by Jeffrey Giansiracusa for Chain complexes of vector bundles