Exponential Equations - MathOverflow [closed]most recent 30 from http://mathoverflow.net2013-06-19T15:40:15Zhttp://mathoverflow.net/feeds/question/75345http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/75345/exponential-equationsExponential EquationsMartin Arnolf2011-09-13T19:36:44Z2011-09-13T19:59:17Z
<p>How do you find an analytical solution for 3^x-x=4?</p>
http://mathoverflow.net/questions/75345/exponential-equations/75348#75348Answer by Alex R. for Exponential EquationsAlex R.2011-09-13T19:59:17Z2011-09-13T19:59:17Z<p>If you want, you can use <a href="http://en.wikipedia.org/wiki/Lambert_W_function" rel="nofollow">Lambert's W function</a>. Let $z:=x+4$, so that the equation becomes $3^{z-4}=z$, so that $-3^{-4}=-z3^{-z}$, which upon inverting with Lambert's $W$ gives:</p>
<p>$x=-\frac{W(-\ln(3)3^{-4})}{\ln(3)}-4$</p>
<p>In particular, $W(r)$ has a nice taylor expansion:</p>
<p>$W(r)=\sum_{n=1}^\infty \frac{(-1)^{n-1}n^{n-2}}{(n-1)!}r^n$</p>