Locally compact, complete, bounded spaces - MathOverflow [closed]most recent 30 from http://mathoverflow.net2013-05-21T09:06:24Zhttp://mathoverflow.net/feeds/question/73170http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/73170/locally-compact-complete-bounded-spacesLocally compact, complete, bounded spacesPablo Pigeon2011-08-18T17:40:06Z2011-08-18T20:13:34Z
<p>Is every locally compact, complete, bounded space compact?</p>
<p>It seems that this fact is implicitly used in the definition of Gromov-Hausdorff convergence for pointed spaces on wikipedia, but I'm not able to prove it.</p>
http://mathoverflow.net/questions/73170/locally-compact-complete-bounded-spaces/73173#73173Answer by Stefan Geschke for Locally compact, complete, bounded spacesStefan Geschke2011-08-18T18:47:46Z2011-08-18T20:13:34Z<p>A metric space is compact if and only if it is complete and totally bounded. This is the Heine-Borel theorem. Is this what you are looking for?</p>
http://mathoverflow.net/questions/73170/locally-compact-complete-bounded-spaces/73174#73174Answer by Mahdi Majidi-Zolbanin for Locally compact, complete, bounded spacesMahdi Majidi-Zolbanin2011-08-18T18:48:50Z2011-08-18T18:48:50Z<p>I don't believe this is true. For example, take an <em>infinite</em> set and put discrete metric on it, that is, $d(x,y)=0$ if $x=y$ and $d(x,y)=1$ if $x\not=y$. Then I believe this is locally compact, complete and bounded, but it is not compact. Did I understand your question correctly?</p>