Separability of continuous functions with compact support - MathOverflow [closed]most recent 30 from http://mathoverflow.net2013-05-24T00:44:48Zhttp://mathoverflow.net/feeds/question/67763http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/67763/separability-of-continuous-functions-with-compact-supportSeparability of continuous functions with compact supportfjodor_d2011-06-14T14:06:34Z2011-06-14T14:25:47Z
<p>Hi,</p>
<p>is the space $C_0(\mathbb{R}^m)$, $m \in \mathbb{N}$ of continuous functions with compact support separable? If yes: where can I find a proof for that?</p>
<p>Please note: this is not a duplicate of this question <a href="http://mathoverflow.net/questions/54026/separability-of-a-certain-space-of-continuous-functions" rel="nofollow">(click)</a>, since I asked for compact support.</p>
<p>The reason I'm asking is: here <a href="http://www.google.com/url?sa=t&source=web&cd=1&ved=0CCMQFjAA&url=http%3A%2F%2Fdiffusion.jlu.edu.cn%2Fseminar%2Ffiles%2FEvans.pdf&rct=j&q=evans%20weak%20convergence%20methods%20for%20nonlinear%20partial%20differential%20equations&ei=BGj3Tav2N5C_gQf8zpGTDA&usg=AFQjCNF3kplJO_opo1rtuN_WhvNHkaYeHg&cad=rja" rel="nofollow">(click)</a> the author (L.C. Evans) seems to use the fact on page 18 (page 20 of the pdf) first line without mentioning the difficulty, that $\mathbb{R}$ isn't compact. The entire proof is senseless without this fact.</p>
<p>Your help is very much appreciated!
Thanks!</p>
http://mathoverflow.net/questions/67763/separability-of-continuous-functions-with-compact-support/67769#67769Answer by unknown (google) for Separability of continuous functions with compact supportunknown (google)2011-06-14T14:25:47Z2011-06-14T14:25:47Z<p>Each $C([-N,N]^m)$ is separable, and so is the subspace $X_N\subseteq C([-N,N]^m)$ consisting of functions which vanish on the boundary $\partial[-N,N]^m$. Take a countable dense subset of each $X_N$, and take the union over all integers $N$. This is then a countable dense subset of $C_0(\mathbb R^m)$.</p>