An extension of Gaussian Isoperimetry - MathOverflow most recent 30 from http://mathoverflow.net2013-06-20T09:45:08Zhttp://mathoverflow.net/feeds/question/65772http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/65772/an-extension-of-gaussian-isoperimetryAn extension of Gaussian IsoperimetryBratt2011-05-23T16:39:20Z2011-05-24T12:39:16Z
<p>The Gaussian isoperimetric inequality (Tsirelson,Sudakov, Borell) states that among all sets of given Gaussian measure in the n-dimensional Euclidean space, half-spaces have the minimal Gaussian boundary measure.
Suppose we put an additional restriction on the set, that it should be symmetric about the origin. Then can we conclude that quarter-spaces (intuitively the first and third quadrant in 2-dimensions, say) have the minimal Gaussian boundary measure?</p>
http://mathoverflow.net/questions/65772/an-extension-of-gaussian-isoperimetry/65784#65784Answer by Igor Rivin for An extension of Gaussian IsoperimetryIgor Rivin2011-05-23T18:46:13Z2011-05-23T18:46:13Z<p>Answering more @Bratt's comment than the original question: Talagrand's book</p>
<p>people.math.jussieu.fr/~talagran/book.ps.gz</p>
<p>Seems quite nice.</p>
http://mathoverflow.net/questions/65772/an-extension-of-gaussian-isoperimetry/65845#65845Answer by Ryan O'Donnell for An extension of Gaussian IsoperimetryRyan O'Donnell2011-05-24T12:39:16Z2011-05-24T12:39:16Z<p>My guess is that the optimizer is actually a "strip"; i.e., a set of the form {$x : -t \leq x_1 \leq t$}. But I'm somewhat sure that the solution to this problem is not known. You might take a look at the discussion surrounding after Corollary 3.6 in this paper by Klartag and Regev:</p>
<p><a href="http://eccc.hpi-web.de/report/2010/140/" rel="nofollow">http://eccc.hpi-web.de/report/2010/140/</a></p>
<p>Barthe may also have some relevant papers.</p>