Is every regular (excellent) scheme separated? - MathOverflow most recent 30 from http://mathoverflow.net2013-05-25T08:54:30Zhttp://mathoverflow.net/feeds/question/63592http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/63592/is-every-regular-excellent-scheme-separatedIs every regular (excellent) scheme separated?Mikhail Bondarko2011-05-01T08:58:05Z2011-05-01T09:36:49Z
<p>Sorry for one more stupid AG question. I need schemes that are regular, excellent and separated. Are these three conditions independent?</p>
http://mathoverflow.net/questions/63592/is-every-regular-excellent-scheme-separated/63594#63594Answer by Kevin Ventullo for Is every regular (excellent) scheme separated?Kevin Ventullo2011-05-01T09:36:49Z2011-05-01T09:36:49Z<p><strong>-</strong> Separated, excellent, regular: Spec$(k)$.</p>
<p><strong>-</strong> Separated, excellent, not regular: Spec$(k[\epsilon]/\epsilon^2)$.</p>
<p><strong>-</strong> Separated, not excellent, regular: See <a href="http://en.wikipedia.org/wiki/Excellent_ring" rel="nofollow">http://en.wikipedia.org/wiki/Excellent_ring</a></p>
<p><strong>-</strong> Separated, not excellent, not regular: Spec$(k[\epsilon_1,\epsilon_2,\ldots]/\langle\epsilon_1^2,\epsilon_2^2,\ldots\rangle$.</p>
<p><strong>-</strong> Not separated, excellent, regular: Glue Spec$(\mathbb{Z})$ to itself along the complement of a closed point.</p>
<p>To get the other three, take the disjoint union of the fifth example with any of the second, third, or fourth examples.</p>