Niemeier lattices and theta functions - MathOverflow most recent 30 from http://mathoverflow.net2013-05-19T12:51:47Zhttp://mathoverflow.net/feeds/question/62070http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/62070/niemeier-lattices-and-theta-functionsNiemeier lattices and theta functionsflor.ian sprung2011-04-18T01:08:05Z2011-04-18T21:31:34Z
<p>I have an extremely elementary question. Let's say someone randomly hands you a theta function associated to a Niemeier lattice (unimodular even, n=24). What can you say about which Niemeier lattice gave you this theta function in the first place?</p>
http://mathoverflow.net/questions/62070/niemeier-lattices-and-theta-functions/62071#62071Answer by Henry Cohn for Niemeier lattices and theta functionsHenry Cohn2011-04-18T01:25:51Z2011-04-18T01:25:51Z<p>The theta series for a Niemeier lattice determines the lattice in most cases, but there are five ambiguous pairs.</p>
<p>The theta series of an even unimodular lattice must be a polynomial in the theta series of $E_8$ and $\Lambda_{24}$ (this is a modular forms calculation). Thus, for Niemeier lattices, it must be a linear combination of those for $E_8^3$ and $\Lambda_{24}$. The constant term must be $1$, so there is one remaining degree of freedom. This means the theta series for a Niemeier lattice is determined by how many roots (i.e., vectors of norm $2$) it has. There are five pairs of Niemeier lattices with the same number of roots, but no triples.</p>