Slight Alteration to a Diophantine Result - MathOverflow most recent 30 from http://mathoverflow.net2013-05-26T08:35:05Zhttp://mathoverflow.net/feeds/question/61775http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/61775/slight-alteration-to-a-diophantine-resultSlight Alteration to a Diophantine ResultRichard Voepel2011-04-15T01:56:04Z2011-04-17T06:15:28Z
<p>Hello all!</p>
<p>In the pursuit of a minor research problem I was pointed in the direction of an interesting result in the realm of Diophantine Analysis. The content of the result follows:</p>
<p>$\frac{ax^{n+2l}-1}{ax^{n}-1} = y^2$ has a solution in the natural numbers for $a$, $x$, $n$, and $l$, with $x>1$ and $y$ a rational number, if and only if the following conditions are met:</p>
<ul>
<li>$2|l$</li>
<li>$a = \frac{3^{l-1}+1}{4}$</li>
<li>$x=3$</li>
<li>$n=1$</li>
<li>$y=\pm (3^l +2)$</li>
</ul>
<p>I am looking to make a slight alteration to this theorem for use in my research (though the term should be interpreted lightly), by changing $y^2$ to $3y^2$. However, after conferring with one of my professors, I was told such a theorem may already exist!</p>
<p>Does anyone know of this (or these) results, and would be willing to suggest a reference? If no such theorem exists, does anyone have any pointers on a good approach to this problem?</p>
<p>Thank you all in advance for your time and help!</p>
<p>-Richard Voepel</p>
<p>[EDIT]</p>
<p>I first read this result from one of my professor's papers, though I was told directly this was not the first paper to provide such a result. Here is a link.</p>
<p><a href="http://www.math.sc.edu/~filaseta/papers/DiophantinePaper2006.pdf" rel="nofollow">http://www.math.sc.edu/~filaseta/papers/DiophantinePaper2006.pdf</a></p>