Tensor product decomposition of V and g - MathOverflow most recent 30 from http://mathoverflow.net2013-05-21T10:44:03Zhttp://mathoverflow.net/feeds/question/61683http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/61683/tensor-product-decomposition-of-v-and-gTensor product decomposition of V and g Anton Galaev2011-04-14T11:19:03Z2011-04-14T18:18:22Z
<p>Let $g$ be a simple complex Lie algebra with an irreducible representation $g\subset so(V)$ with the highest weight $\Lambda$.</p>
<p>In the book by Onishchik and Vinberg "Lie groups and algebraic
groups" the following formula is given. If $V_\Lambda$ and $V_M$
are irreducible $g$-modules with the highest weights $\Lambda$ and
$M$, then the multiplicity of $V_N$ in $V_\Lambda\otimes V_M$
equals</p>
<p>$\dim$ { $v\in(V_M)_{N-\Lambda}|(e_i)^{\Lambda_i+1}v=0, i=1,...,l$} </p>
<p>$=
\dim$ {$v\in(V_N)_{\Lambda-M'}|(e_i)^{M'_i+1}v=0, i=1,...,l$},</p>
<p>where $l$ is the rank of $g$, ${e_i,f_i,H_i}$ are canonical
generators of $g$, $\Lambda_i$ are labels on the Dynkin diagram,
and $M'$ is the highest weight of $(V_M)^*$, $(V_M)_{N-\Lambda}$
denotes the weight space of weight $N-\Lambda$.</p>
<p>Taking $V_M=g$, we obtain $$V\otimes g=kV\oplus\oplus_\lambda
V_\lambda,$$ where $k$ is the number of non-zero labels on the
Dynkin diagram of $g$ defining the representation $g\subset
so(V)$, and $V_\lambda$ are irreducible modules different from $V$
with the the highest weights $\lambda$ that are pairwise
different. Of course, one of the modules $V_\lambda$ is
$V_{\Lambda+\delta}$, $\delta$ is the highest root.</p>
<p>Are there some other formulas that may give more information about
$V_\lambda$? I would like to have an expression for an element
(not necessary of the highest vector) of each $V_\lambda$. Is it
possible that $V_\lambda$ contains an element of the form
$v\otimes A$, where $v\in V$, $A\in g$?</p>
<p>I am classifying irreducible subalgebras $g\subset so(V)$ that
admit linear maps from $V$ to $g$ satisfying some equation. I
guess that only $V_{\Lambda+\delta}$ may consist of such maps. To
show that other $V_\lambda$ do not consist of such maps, I need to
take some element from these modules and to check the equation.</p>
<p>The above formulas show that to each $V_\lambda$ there is a
preferred root space in $g$ of weight $\lambda-\Lambda$ and a line
in $V_\Lambda$ of weight $\lambda-\delta$. How the elements from
these lines can be used?</p>
http://mathoverflow.net/questions/61683/tensor-product-decomposition-of-v-and-g/61706#61706Answer by Bruce Westbury for Tensor product decomposition of V and g Bruce Westbury2011-04-14T14:51:04Z2011-04-14T16:54:27Z<p>I think the formula you are looking for is $V(\mu)\otimes g\cong kV(\mu) \oplus \oplus_\alpha V(\mu+\alpha)$ where the sum is over roots $\alpha$ such that $\mu+\alpha$ is a dominant weight. Here $V(\lambda)$ is irreducible with highest weight $\lambda$ for $\lambda$ an integral dominant weight.</p>