A question concerning separate and joint continuity of bilinear maps - MathOverflow most recent 30 from http://mathoverflow.net2013-05-18T23:41:47Zhttp://mathoverflow.net/feeds/question/60953http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/60953/a-question-concerning-separate-and-joint-continuity-of-bilinear-mapsA question concerning separate and joint continuity of bilinear mapsJustin Moore2011-04-07T15:40:03Z2011-04-07T16:27:29Z
<p>Suppose that $V$ is a locally convex topological vector space and $f:V^2 \to V$ is a bilinear map. Suppose that $C \subseteq V$ is compact and convex, $f$ maps $C^2$ into $C$ and
$f \restriction C^2$ is separately continuous.
Must $f \restriction C^2$ be jointly continuous?</p>
<p>In the particular application I have in mind, $V = \ell_\infty^*$ with the weak* topology.
Moreover the function $f$ is injective.
I suspect even in this setting that this is false.</p>
<p>I am also interested in a good reference for the optimal results of concerning separate and joint continuity of bilinear maps.
Ideally this would be written for someone who is not a functional analyst.</p>
http://mathoverflow.net/questions/60953/a-question-concerning-separate-and-joint-continuity-of-bilinear-maps/60962#60962Answer by Matthew Daws for A question concerning separate and joint continuity of bilinear mapsMatthew Daws2011-04-07T16:27:29Z2011-04-07T16:27:29Z<p>A personal obsession is (weakly) almost period functions. Let $G$ be a discrete group (you can work more generally) and for $f\in \ell^\infty(G)$ let $O(f)$ be the set of translate of $f$ by the group action. Set
<code>\begin{align*} AP(G) = \{ f\in \ell^\infty(G) : O(f)\text{ is relatively compact}\}, \\
WAP(G) = \{ f\in \ell^\infty(G) : O(f)\text{ is weakly relatively compact}\}. \end{align*}</code>
Then these are unital sub-<code>$C^*$</code>-algebras of $\ell^\infty(G)$ and so have character spaces $G^{AP}$ and $G^{WAP}$. You can extend the product from $G$ to these: then the product on $G^{AP}$ is jointly continuous, but that on $G^{WAP}$ only separately jointly continuous. Translated back to algebra, this means that the measure spaces $M(G^{AP})$ and $M(G^{WAP})$ become Banach algebras for the convolution product. The continuity translates to say that the product on $M(G^{WAP})$ is separately weak<code>$^*$</code>-continuous, and that on $M(G^{AP})$ is even jointly weak<code>$^*$</code>-continuous on bounded sets.</p>
<p>So that gives an example: if $C$ is the closed unit ball of $M(G^{WAP})$ and $f$ is the product map, then $f$ satisfies your requirements, but $f$ is not jointly continuous unless $WAP(G) = AP(G)$ (I think-- this last claim needs a little chasing of definitions). If $G$ is abelian then $G^{AP}$ is the classical Bohr compacitification, but $G^{WAP}$ is much larger. There are books by Berglund (and coauthors) on this topic; they do, IMHO, need a functional analysis background.</p>
<p>Surely there are easier examples for what you want though. (And $f$ is not injective in my example).</p>