Convergence of Fourier series in L^{\infty}-norm - MathOverflow [closed]most recent 30 from http://mathoverflow.net2013-05-26T06:57:27Zhttp://mathoverflow.net/feeds/question/60427http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/60427/convergence-of-fourier-series-in-l-infty-normConvergence of Fourier series in L^{\infty}-normAcky2011-04-03T11:53:47Z2011-04-03T13:44:43Z
<p>As we know, for <code>$1<p<\infty$</code>, the Fourier series of <code>$f\in L^{p}(T)$</code> converges to <code>$f$</code> in <code>$L^{p}$</code>-norm.
But is there any results concerning the convergence of Fourier series in <code>$L^{\infty}$</code>-norm?
Since <code>$L^{\infty}(T)$</code> is not separable, the trigonometric system fails to form a Schauder basis of <code>$L^{\infty}(T)$</code>, this implies that the Fourier series of <code>$L^{\infty}(T)$</code>-functions fails to converge in <code>$L^{\infty}$</code>-norm. But does the Fourier series of <code>$f$</code> converge in <code>$L^{\infty}$</code>-norm for every $f\in C(T)$?</p>
http://mathoverflow.net/questions/60427/convergence-of-fourier-series-in-l-infty-norm/60432#60432Answer by Shaoming Guo for Convergence of Fourier series in L^{\infty}-normShaoming Guo2011-04-03T12:58:21Z2011-04-03T12:58:21Z<p>I think you can find the answer in P191 "Classical Fourier Analysis",second edition, Loukas Grafakos</p>
http://mathoverflow.net/questions/60427/convergence-of-fourier-series-in-l-infty-norm/60435#60435Answer by Gian Maria Dall'Ara for Convergence of Fourier series in L^{\infty}-normGian Maria Dall'Ara2011-04-03T13:31:35Z2011-04-03T13:44:43Z<p>If Fourier series of continuous functions would converge in $L^\infty$, then, by the Uniform Boundedness Principle, the operator norms in $C(\mathbb{T})$ of the partial Fourier series operators $S_Nf(t):=\sum_{n=-N}^N\hat{f}(n)e^{int}$ would be uniformly bounded. You can find, for example in Katznelson book, a proof of the fact that such norms diverge logarithmically.</p>