Necessary condition for a branch point - MathOverflow most recent 30 from http://mathoverflow.net2013-05-23T12:38:40Zhttp://mathoverflow.net/feeds/question/59614http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/59614/necessary-condition-for-a-branch-pointNecessary condition for a branch pointdoob2011-03-25T21:42:54Z2011-03-26T00:18:52Z
<p>If I have a function $f(z,\alpha)$ (let's keep it a polynomial of order $\geq 2$ in $z$, for simplicity), what would be a necessary condition for there to be branch points for this function? A friend mentioned that $f(z,\alpha)$ and $f_{\alpha}(z,\alpha)$, where the second term is the partial derivative w.r.t. $\alpha$, should have a common root. I don't see this intuitively. Is this true? If so, why?</p>
http://mathoverflow.net/questions/59614/necessary-condition-for-a-branch-point/59622#59622Answer by Francesco Polizzi for Necessary condition for a branch pointFrancesco Polizzi2011-03-26T00:12:49Z2011-03-26T00:18:52Z<p>Your question is not very clear. However, I guess you are asking for the branch points of the cover of $\mathbb{C}$ defined by $f(z, \alpha)=0$.</p>
<p>In this case, let us assume for the sake of symplicity that $f(z, \alpha)$ is <em>monic</em> in $z$; then </p>
<p>$f(z, \alpha)=z^n + f_{n-1}(\alpha)z^{n-1}+ \cdots + f_0(\alpha)$. </p>
<p>The Riemann surface $X \subset \mathbb{C}^2$ defined by $f(z, \alpha)=0$ is a cover $X \to \mathbb{C}$ of degree $n$, defined by $(z, \alpha) \to \alpha$.</p>
<p>The branch points of this cover are precisely the points $\bar{\alpha}$ such that $f(z, \bar{\alpha})$ has a multiple root. This is equivalent to require that $f(z, \bar{\alpha})$ and $f_z(z, \bar{\alpha})$ have a common root.</p>
<p>In other words, the branch points are the roots of the equation</p>
<p>$\textrm{Disc}_z(f)=0,$</p>
<p>where $\textrm{Disc}_z(f)$ is the discriminant of $f$ with respect to $z$, i.e. the resultant of $f$ and $\partial f / \partial z$ computed with respect to $z$.</p>
<p>For instance, the branch points of the Riemann surface defined by</p>
<p>$z^3+f_1(\alpha)z+f_0(\alpha)=0$</p>
<p>are the roots of</p>
<p>$4 f_1(\alpha)^3+27 f_0(\alpha)^2=0$.</p>