Fast series for pi - MathOverflow most recent 30 from http://mathoverflow.net2013-05-25T01:26:34Zhttp://mathoverflow.net/feeds/question/56328http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/56328/fast-series-for-piFast series for piStanley Yao Xiao2011-02-22T21:46:36Z2011-04-03T08:16:31Z
<p>A quick perusal of the wikipedia page for $\pi$ yields a large collection of known series for $\pi$. In particular, these series are hypergeometric in nature, and have large (but finite) radius of convergence. </p>
<p>My first question is, what is the best known series for $\pi$? Namely, a series of the form above with the largest radius of convergence.</p>
<p>My second question is one asked by Herbert Wilf (http://www.math.upenn.edu/~wilf/website/UnsolvedProblems.pdf), which is to ask whether there exists a sequence $(a_n)$ with $a_{n+1}/a_n$ a rational functional of $n$ for all $n$, and the function $f(z) = \displaystyle \sum_{n=0}^\infty a_n z^n$ is an entire function, and $f(1) = \pi$. Presumably, such a function is not known to exist yet. Can anyone give any recent works that advances our understanding on this problem, or give some insight as to why such a function is so difficult to find?</p>
<p>Thanks!</p>
http://mathoverflow.net/questions/56328/fast-series-for-pi/56348#56348Answer by Gerry Myerson for Fast series for piGerry Myerson2011-02-23T01:04:31Z2011-02-23T01:45:09Z<p>I like Andre Henriques' rephrasing. The Borwein, Bailey, Plouffe series, with $$a_n={1\over16^n}\left({4\over8n+1}-{2\over8n+4}-{1\over8n+5}-{1\over8n+6}\right)$$ would have radius of convergence $r=16$. Bellard gives a more complicated one with $r=1024$. Pschill has one with 21 terms and $r=2^{30}$. If you'll accept $f(1)=1/\pi$, D and G Chudnovsky give $$a_n={12\over\sqrt{640320^3}}(-1)^n{(6n)!\over(n!)^3(3n)!}{13591409+54514013n\over(640320^3)^n}$$ All of these are taken from Chapter 16 of Arndt and Haenel, $\pi$ Unleashed, which gives full bibliographic citations. </p>
<p>EDIT: See also <a href="http://mathworld.wolfram.com/PiFormulas.html" rel="nofollow">http://mathworld.wolfram.com/PiFormulas.html</a> in particular formulas 93-96 where each term gives another 50 digits of $1/\pi$ (which I guess corresponds to $r$ roughly $10^{50}$). Somehow, the series for $1/\pi$ seem to do better than those for $\pi$. I know there are people who would like us to abandon $\pi$ in favor of $2\pi$, but maybe we should really be expressing things in terms of $1/(2\pi)$. </p>
http://mathoverflow.net/questions/56328/fast-series-for-pi/60363#60363Answer by Gert Almkvist for Fast series for piGert Almkvist2011-04-02T15:04:40Z2011-04-02T15:04:40Z<p>In Almkvist-Krattenthaler-Petersson:"Some new formulas for Pi" arXiv 2003?, Exp. Math 12(2003) 441-456 it is shown that there exist formulas for Pi where each term gives N new digits for any given N.
Gert Almkvist</p>