Notation for a representable functor - MathOverflow most recent 30 from http://mathoverflow.net2013-05-20T14:35:01Zhttp://mathoverflow.net/feeds/question/54076http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/54076/notation-for-a-representable-functorNotation for a representable functorMartin Brandenburg2011-02-02T08:40:39Z2011-02-03T00:13:07Z
<p>For an object $X$ of a category, $h_X$ is the contravariant functor represented by $X$, i.e. $h_X = Hom(-,X)$.</p>
<p><strong>Question</strong> a) Who invented this notation? (My guess: Grothendieck)</p>
<p>b) Is there a special reason why the letter $h$ was chosen? Is it in an abbreviation for "homomorphism"?</p>
http://mathoverflow.net/questions/54076/notation-for-a-representable-functor/54085#54085Answer by Leo Alonso for Notation for a representable functorLeo Alonso2011-02-02T10:47:34Z2011-02-02T10:47:34Z<p>a) It was invented by Grothendieck, see EGA I, Springer edition, especially chapter 0, discussion of representable functors.</p>
<p>b) Quite possibly is a shortcut for $Hom$. Sometimes the letter $y$ is used (for Yoneda). The trouble is when you are considering the representable functor defined over several categories, e.g. a category and a subcategory.</p>
<p>Bonus: If you, instead of considering contravariant functors $\mathrm{Sch}^{o} \to \mathrm{Set}$, use covariant functors $\mathrm{Aff} \to \mathrm{Set}$ the notation used in EGA is $h_X^{o}$. Perhaps the reason is that Yoneda's map is contravariant in this case.</p>