A homomorphism on $\pi_1(X)$ descending to a homomorphism on its abelianization - MathOverflow [closed]most recent 30 from http://mathoverflow.net2013-06-19T20:11:55Zhttp://mathoverflow.net/feeds/question/53639http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/53639/a-homomorphism-on-pi-1x-descending-to-a-homomorphism-on-its-abelianizationA homomorphism on $\pi_1(X)$ descending to a homomorphism on its abelianizationSputnik2011-01-28T18:08:30Z2011-01-28T18:08:30Z
<p>Let $X$ be a path-connected topological space. Denote $\pi(X)$ as the fundamental group (note this doesn't need a basepoint up to isomorphism, as $X$ is path-connected) and denote $H_1(X)$ as the 1st singular homology group. Let:</p>
<p>$\phi : \pi_1(X) \to H_1(X)$</p>
<p>be the function that sends the homotopy class of a loop $f$ to the homology class of the singular 1-cycle $f$. It can be checked that $\phi$ is well-defined and a homomorphism. I also have reason to believe that it naturally descends to a homomorphism:</p>
<p>$\overline{\phi}: \pi_1(X)_{ab} \to H_1(X)$</p>
<p>on the abelianization of the fundamental group. Could anyone shed a little more light on why this is the case? In particular, is $\overline{\phi}$ uniquely determined by $\phi$ (if so, how it uniquely determined), and why is it a homomorphism?</p>