The geometry of Nadirashvili's complete, bounded, negative curvature surface - MathOverflow most recent 30 from http://mathoverflow.net 2013-05-22T04:16:09Z http://mathoverflow.net/feeds/question/52851 http://www.creativecommons.org/licenses/by-nc/2.5/rdf http://mathoverflow.net/questions/52851/the-geometry-of-nadirashvilis-complete-bounded-negative-curvature-surface The geometry of Nadirashvili's complete, bounded, negative curvature surface Joseph O'Rourke 2011-01-22T18:20:14Z 2011-03-30T14:15:07Z <p>I would like to understand the geometric structure of a surface that Nadirashvili constructed which resolved what was known as Hadamard's Conjecture. Perhaps in the 15 years since his construction, others have redescribed the example, and perhaps even made a graphics image of it?</p> <p><b>Background.</b> Hilbert's theorem that implies that the hyperbolic plane cannot be realized as a surfaces in $\mathbb{R}^3$ is well known. Perhaps less well known is Hadamard's Conjecture, which asked if there is a complete negative curvature surface in a bounded region of $\mathbb{R}^3$. This is discussed at some length in Burago and Zallgaller's book <em>Geometry III: Theory of Surfaces</em>. The problem was solved after that 1989 book was written, as Berger explains in <em>A Panoramic View of Riemannian Geometry</em> (p.135):</p> <p><br /><img src="http://cs.smith.edu/~orourke/MathOverflow/Berger135.jpg" alt="alt text"><br /></p> <p>(Incidentally, the answer to this related MO question on <a href="http://mathoverflow.net/questions/32597/compact-surfaces-of-negative-curvature" rel="nofollow">Compact Surfaces of Negative Curvature</a> does not resolve my question, as it relies on Burago and Zallgaller.)</p> <p>Here is the citation:</p> <blockquote> <p>Nikolaj Nadirashvili, "Hadamard's and Calabi-Yau's conjectures on negatively curved and minimal surfaces." <em>Invent. Math.</em> 126(3) (1996), 457–465.</p> </blockquote> <p>The main theorem is this:</p> <blockquote> <p><b>Theorem.</b> There exists a complete surface of negative Gaussian curvature minimally immersed in $\mathbb{R}^3$ which is a subset of the unit ball.</p> </blockquote> <p>I have studied the paper, but my grasp of the underlying mathematics is not strong enough to convert his description into a geometric picture. If anyone knows of later discussions that might help, I would appreciate pointers or references. Thanks!</p> <p><b>Edit.</b> I was not able to access MathReviews until now. This is from the review by M. Cai (MR1419004 (98d:53014)):</p> <blockquote> <p>For the proof, the author starts with a minimal immersion of the unit disk into a fixed ball in $\mathbb{R}^3$ with the Gaussian curvature of the immersed surface being negative, then he inductively defines a sequence of minimal immersions of negative curvature into the fixed ball in such a way that the sequence converges to a complete immersion.</p> </blockquote> <p>This helps.</p> http://mathoverflow.net/questions/52851/the-geometry-of-nadirashvilis-complete-bounded-negative-curvature-surface/60069#60069 Answer by Tom Mrowka for The geometry of Nadirashvili's complete, bounded, negative curvature surface Tom Mrowka 2011-03-30T14:01:55Z 2011-03-30T14:15:07Z <p>In fact the conjecture becomes true if you add embedded to the hypothesis according to a theorem of Colding and Minicozzi. (Colding, Tobias H.; Minicozzi, William P., II The Calabi-Yau conjectures for embedded surfaces. Ann. of Math. (2) 167 (2008), no. 1, 211–243.)</p> <p>Who knows what Hadamard actually had in mind.</p> <p>(Sorry this should have been a comment, its certainly not an answer to the question.)</p>