matrices of Lie algebra of Dynkin diagram B2 - MathOverflow [closed]most recent 30 from http://mathoverflow.net2013-05-25T08:18:56Zhttp://mathoverflow.net/feeds/question/52259http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/52259/matrices-of-lie-algebra-of-dynkin-diagram-b2matrices of Lie algebra of Dynkin diagram B2garretstar2011-01-16T19:33:00Z2011-01-31T01:22:13Z
<p>The Lie algebra $so_5$ has 10 elements and its root structure is given by the Dynkin diagram B2. I have been having trouble creating an explicit $5 \times 5$ complex matrix representation of its 10 elements from its Cartan matrix. I would greatly appreciate help with this.</p>
http://mathoverflow.net/questions/52259/matrices-of-lie-algebra-of-dynkin-diagram-b2/52277#52277Answer by Allen Knutson for matrices of Lie algebra of Dynkin diagram B2Allen Knutson2011-01-17T01:06:53Z2011-01-17T01:06:53Z<p>While I'm not sure this question is appropriate for this site, here goes.</p>
<p>First, you need a maximal torus. Inside SO(5) we have SO(4) and then SO(2) x SO(2).</p>
<p>Write your antisymmetric matrices as</p>
<p>$$\begin{matrix}
aJ & C & v
\end{matrix} $$
$$\begin{matrix}
-C^T & bJ & w
\end{matrix} $$
$$\begin{matrix}
-v^T & -w^T & 0
\end{matrix} $$
where
$J = \left( {0\atop -1}{1\atop 0} \right) $, $C$ is square, and $v$ and $w$ are columns. Then the $a$ and $b$ parts are the torus, the $v$ gets you the $\pm x_1$ weights, the $w$ gets you the $\pm x_2$, and the $C$ gets you the $\pm x_1\pm x_2$. </p>
<p>Taking $x_1$ and $x_2 - x_1$ as simple roots, the $e_{x_1}$ is
$$ 0 0 0 0 1 $$
$$ 0 0 0 0 i $$
$$ 0 0 0 0 0 $$
$$ 0 0 0 0 0 $$
$$ -1 -i 0 0 0 $$
and the $e_{x_2-x_1}$ is
$$ 0 0 1 i 0 $$
$$ 0 0 i -1 0 $$
$$ -1 -i 0 0 0 $$
$$ -i 1 0 0 0 $$
$$ 0 0 0 0 0 $$
Sorry for the ugly matrices -- I'm having trouble getting the matrix environment working here.</p>