co-$A_\infty$ spaces - MathOverflow most recent 30 from http://mathoverflow.net2013-06-19T03:08:04Zhttp://mathoverflow.net/feeds/question/50298http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/50298/co-a-infty-spacesco-$A_\infty$ spacesJohn Klein2010-12-24T18:06:53Z2011-01-29T02:22:13Z
<p>A co-$A_n$ space is a based space $Y$ equipped with a co-action by the Stasheff associahedron operad $K_\bullet$. This means that $Y$ is comes with certain maps $c_n: Y \times K_n \to Y^{\vee n}$, $n = 2,3,\dots$ that are inductively described (the definition of $c_n$ uses $c_{n-1}$ as input; the map $c_2$ is a co-$H$ structure). The suspension of a based space $X$ has the structure of a co-$A_\infty$ space.</p>
<p>Assume $Y$ is $2$-connected and has the homotopy type of a finite complex. Then
Schwaenzl, Vogt and I showed that a co-$A_\infty$ space $Y$ desuspends to a space $X$ in the
sense that there's a weak equivalence $\Sigma X \simeq Y$. </p>
<p>However we didn't try to check that the given weak equivalence is compatible in the co-$A_\infty$ sense. Part of the problem is that a morphism $f: Y \to Z$ of co-$A_\infty$ spaces should amount a co-$A_\infty$-structure on its mapping cylinder restricting to the given ones on $X \times 1$ and $Y$. However, this doesn't form a category: it's an $\infty$-category. </p>
<p>Now to my questions:</p>
<p>Question 1: is there a documented proof somewhere that the functor which assigns to a based space $X$ its suspension (considered as an co-$A_\infty$ space) induces an equivalence between the homotopy category of $1$-connected spaces and $2$-connected co-$A_\infty$ spaces?</p>
<p>Presumably, such a proof should be Hilton-Eckmann dual to one of the main results in the Book of Boardman and Vogt. </p>
<p>Question 2: Do function spaces coincide up to weak equivalence under this functor? That is,
is the map $$\hom_{\text{Top}_*}(X,X') \to
\hom_{\text{co-}A_\infty}(\Sigma X,\Sigma X')$$
A weak equivalence under suitable hypotheses on $X$ and $X'$?</p>
<p>By $\hom$ in each case, I mean topologized mapping spaces.</p>
<p>How would one go about proving a result like this?</p>
http://mathoverflow.net/questions/50298/co-a-infty-spaces/50841#50841Answer by jim stasheff for co-$A_\infty$ spacesjim stasheff2011-01-01T01:42:26Z2011-01-01T01:42:26Z<p>I have the feeling many of us would agree those statements `should' be true, but I can't think of
anyone who wrote things down publicly. Why not ask at alg-top? overflow requires active logging in
alg-top doesn't</p>
<p>jim</p>