Is every ring the direct limit of Noetherian rings? - MathOverflow most recent 30 from http://mathoverflow.net2013-05-24T01:38:26Zhttp://mathoverflow.net/feeds/question/48035http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/48035/is-every-ring-the-direct-limit-of-noetherian-ringsIs every ring the direct limit of Noetherian rings?Achilleas K2010-12-02T11:29:42Z2011-11-12T14:48:02Z
<p>Are there any examples of commutative rings that do not occur as direct limits of Noetherian rings?</p>
http://mathoverflow.net/questions/48035/is-every-ring-the-direct-limit-of-noetherian-rings/48037#48037Answer by Martin Brandenburg for Is every ring the direct limit of Noetherian rings?Martin Brandenburg2010-12-02T11:36:08Z2011-11-12T14:48:02Z<p>Every commutative ring is the directed colimit of its subrings that are finitely generated as $\mathbb{Z}$-algebras. The Hilbert Basis Theorem implies that these subrings are noetherian. Actually this method is used in EGA IV, §8.9 to generalize some theorems from noetherian schemes to more general schemes.</p>