Natural numbers n which satisfy gnu(n)=n? - MathOverflow most recent 30 from http://mathoverflow.net2013-05-25T16:12:11Zhttp://mathoverflow.net/feeds/question/46444http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/46444/natural-numbers-n-which-satisfy-gnunnNatural numbers n which satisfy gnu(n)=n?Glen M Wilson2010-11-18T01:37:12Z2010-11-18T04:56:21Z
<p>Are there any natural numbers $n$ (other than 1) for which $gnu(n)=n$? We define $gnu(n)$ to
be the number of isomorphism classes of groups of order $n$. This question popped into my head today, and I couldn't come up with a proof one way or another. </p>
<p>In the paper by Conway, et al. entitled <a href="http://www.math.auckland.ac.nz/~obrien/research/gnu.pdf%20%22Counting%20Groups%3A%20Gnus,%20Moas,%20and%20other%20Exotica%22" rel="nofollow">"Counting Groups: Gnus, Moas, and other Exotica</a>, Conjecture 10.1 implies that there should be no such natural number $n$ which satisfies $gnu(n)=n$. </p>
<p>Does anybody have an argument to show that there is no natural number $n$ (other than 1) for which $gnu(n)=n$? If it is really straightforward, just say so and I'll work it out for myself when I find time. Thanks! </p>