Finding an appropriate Riemannian metric $G:\mathbb{R}^3\rightarrow\mathbb{R}^{3\times{3}}$ on $\mathbb{R}^3$

2010-10-26T02:10:31Z

I am trying to find a Riemannian metric $G:\mathbb{R}^3\rightarrow\mathbb{R}^{3\times{3}}$ on the manifold $\mathbb{R}^3$ such that $G$ is not uniformly positive definite, and there is no isometry $\phi:\mathbb{R}^3\rightarrow\mathbb{R}^3$ satisfying $G=\phi^*I_3$, where $I_3$ is the identity matrix. Moreover, I want $(\mathbb{R}^n,G)$ be geodesically complete. It seems easy to find $G$, but I could not succeed to find any.

Answer by Christian Blatter for Finding an appropriate Riemannian metric $G:\mathbb{R}^3\rightarrow\mathbb{R}^{3\times{3}}$ on $\mathbb{R}^3$

2010-10-26T07:49:17Z

Try $ds^2 = |d{\bf x}|^2/(1+|{\bf x}|^2)$. The resulting metric space is complete since the "horizon" is infinitely far away. But maybe I have misunderstood the notion "not uniformly positive definite".

Finding an appropriate Riemannian metric $G:\mathbb{R}^3\rightarrow\mathbb{R}^{3\times{3}}$ on $\mathbb{R}^3$ - MathOverflow

Finding an appropriate Riemannian metric $G:\mathbb{R}^3\rightarrow\mathbb{R}^{3\times{3}}$ on $\mathbb{R}^3$

Answer by Christian Blatter for Finding an appropriate Riemannian metric $G:\mathbb{R}^3\rightarrow\mathbb{R}^{3\times{3}}$ on $\mathbb{R}^3$