most recent 30 from http://mathoverflow.net 2013-05-25T22:02:22Z http://mathoverflow.net/feeds/question/42693 http://www.creativecommons.org/licenses/by-nc/2.5/rdf http://mathoverflow.net/questions/42693/is-singular-cohomology-representable-by-a-voevodskys-motivic-complex Mikhail Bondarko 2010-10-18T20:22:21Z 2010-10-18T20:22:21Z

<p>For any $c>0$ does there exist an object $C$ of Voevodsky's $DM^{eff}_-$ (over the field of complex numbers) such that for any $i\le c$ and any smooth variety $X$ the $i$-th singular cohomology of $X$ is given by the $i$-th hypercohomology of $C$ at $X$? It seems that I can prove this fact (using qfh-descent), but if somebody has proved this already I would prefer to have a reference.</p>