An eventually different function adding no Solovay real nor dominating function? - MathOverflow most recent 30 from http://mathoverflow.net2013-06-19T15:46:12Zhttp://mathoverflow.net/feeds/question/41447http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/41447/an-eventually-different-function-adding-no-solovay-real-nor-dominating-functionAn eventually different function adding no Solovay real nor dominating function?Bjørn Kjos-Hanssen2010-10-07T19:42:11Z2010-10-14T08:35:17Z
<h1>Definitions</h1>
<p>I believe set theorists have studied all of the following three notions in the context of forcing extensions of a model of ZFC, $M$ (hopefully the terminology is the standard one).</p>
<ol>
<li><p>A function $f:\mathbb N\rightarrow\mathbb N$ is <em>eventually different</em> if for each function $g:\mathbb N\rightarrow\mathbb N$, $g\in M$, the set <code>$\{n: f(n)=g(n)\}$</code> is finite.</p></li>
<li><p>A real $r\in [0,1]$ is a <em>Solovay random real</em> if for each measure-zero subset $S$ of $\mathbb R$ with $S\in M$, we have $r\not\in S$.</p></li>
<li><p>A function $f:\mathbb N\rightarrow\mathbb N$ is <em>dominating</em> if for each function $g:\mathbb N\rightarrow\mathbb N$ in the ground model $M$, the set <code>$\{n: f(n)\le g(n)\}$</code> is finite.
<br></p>
<h1>Motivation</h1></li>
</ol>
<p><br>
An eventually different function that is not too fast-growing is reminiscent of a random real. Can we always use it to construct a random real? The analogous problem in computability theory was quite difficult but has been solved by Kumabe and Lewis (J. LMS, 2009). </p>
<h1>Question</h1>
<blockquote>
<p><strong>I.</strong> Is it possible to add an eventually different function to $M$ while adding neither a Solovay real nor a dominating function?
<br></p>
</blockquote>
<p>EDIT: Now stating the question in the strongest possible form, which is the one Andrés Caicedo answers below.</p>
http://mathoverflow.net/questions/41447/an-eventually-different-function-adding-no-solovay-real-nor-dominating-function/41461#41461Answer by Andres Caicedo for An eventually different function adding no Solovay real nor dominating function?Andres Caicedo2010-10-07T21:54:51Z2010-10-07T21:54:51Z<p>Hi Bjørn, and congratulations to you and Bonnie!</p>
<p>The answer to I is yes. In fact, there is a standard way of doing this, with the "eventually different forcing ${\mathbb E}$". This notion does not add random or dominating reals, and adds an eventually different function. </p>
<p>Conditions have the form $(s, A)$ where $s\in\omega^{<\omega}$ and $A\in[\omega^\omega]^{<\omega}$, with $(s, A)\le(s',A')$ iff $s\supseteq s'$, $A\supseteq A'$, and for all $f\in A'$ and $j\in[|s'|,|s|)$, we have $s(j)\ne f(j)$. (For me, $p\le q$ means that $p$ is stronger.) </p>
<p>This is a nice forcing: It is ccc, in fact, $\sigma$-centered, since any two conditions with the same first coordinate are compatible. But no $\sigma$-centered forcing adds random reals. </p>
<p>That ${\mathbb E}$ does not add dominating reals is a tad more work. But you can find a written proof in section 7.4.B of "Set Theory: On the structure of the real line", by Tomek Bartoszy´nski and Haim Judah. Let me know if you do not have access to a copy. </p>