complete estimates of the error for a well-known asymptotic expression of partition p(n,m) - MathOverflow most recent 30 from http://mathoverflow.net2013-06-20T10:06:16Zhttp://mathoverflow.net/feeds/question/37360http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/37360/complete-estimates-of-the-error-for-a-well-known-asymptotic-expression-of-partiticomplete estimates of the error for a well-known asymptotic expression of partition p(n,m)QHLIU2010-09-01T09:43:21Z2010-09-02T04:14:36Z
<p>Let $p(n,m)$ be the number of partitions of an integer $n$
into integers $\le m$, we have a well-known asymptotic expression: </p>
<p>For a fixed $m$ and $n\to\infty$,
$$p(n,m)=\frac{n^{m-1}}{m!(m-1)!} (1+O(1/n)) $$</p>
<p>My question is: why the error $O(1/n)$ is independent of $m$?
Or how can it be extended for $m$ growing slowly with $n$?
Please help me to find the answer or the references. Thanks. </p>
http://mathoverflow.net/questions/37360/complete-estimates-of-the-error-for-a-well-known-asymptotic-expression-of-partiti/37364#37364Answer by QHLIU for complete estimates of the error for a well-known asymptotic expression of partition p(n,m)QHLIU2010-09-01T10:38:43Z2010-09-01T10:49:42Z<p>Thank Robin Chapman very much for editing.</p>
<p>There is a nice asymptotic expression for partition $q(n,M)$ that denotes the number of partitions of $n$ with $M$ parts all distinct: As $n\to\infty$,</p>
<p>$$ q(n,M)\approx \frac{(n-1)!}{M!(M-1)!(n-M)!}\left( 1+O\left( \frac{M^{3}}{n} \right) \right)$$</p>
<p>Isn't there no similar asymptotic expression for partition $p(n,m)$?</p>
http://mathoverflow.net/questions/37360/complete-estimates-of-the-error-for-a-well-known-asymptotic-expression-of-partiti/37368#37368Answer by Gjergji Zaimi for complete estimates of the error for a well-known asymptotic expression of partition p(n,m)Gjergji Zaimi2010-09-01T11:28:14Z2010-09-01T11:43:44Z<p>I'm not entirely sure of what you are asking, but note that Erdos and Lehner proved <a href="http://projecteuclid.org/DPubS?service=UI&version=1.0&verb=Display&handle=euclid.dmj/1077492649" rel="nofollow">here</a> that
$$p(n,m)\sim \frac{n^{m-1}}{m!(m-1)!}$$ holds for $m=o(n^{1/3})$. In generality for any finite set $A$, with $|A|=m$ and $p(n,A)$ denoting the number of partitions of $n$ with parts from $A$, one has
$$p(n,A)=\frac{1}{\prod_{a\in A}a}\frac{n^{m-1}}{(m-1)!}+O(n^{m-2}).$$</p>
<p>Such estimations can be deduced from the generating function of $p$ by using methods that are described in many books, for example "Analytic Combinatorics" by Flajolet and Sedgewick.</p>
http://mathoverflow.net/questions/37360/complete-estimates-of-the-error-for-a-well-known-asymptotic-expression-of-partiti/37453#37453Answer by Richard Stanley for complete estimates of the error for a well-known asymptotic expression of partition p(n,m)Richard Stanley2010-09-02T02:21:50Z2010-09-02T04:14:36Z<p><a href="http://qjmath.oxfordjournals.org/content/4/1/96.full.pdf+html" rel="nofollow">G. Szekeres, <em>Quart. J. Math. (Oxford)</em> <strong>4</strong>(2) (1953), 96-111</a>, obtains an asymptotic formula for $p(n,m)$ valid uniformly for all $n$ and $m$.</p>