Trying to sum a series (related to catalan numbers perhaps) - MathOverflow most recent 30 from http://mathoverflow.net2013-05-26T08:22:07Zhttp://mathoverflow.net/feeds/question/37253http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/37253/trying-to-sum-a-series-related-to-catalan-numbers-perhapsTrying to sum a series (related to catalan numbers perhaps)David Willis2010-08-31T11:52:42Z2010-08-31T12:04:23Z
<p>Whilst trying to solve a combinatorics problem I am faced with summing this series:</p>
<p>1+ 2C_1 2/(3^2) + 4C_2 (2^2)/(3^4) + 6C_3 (2^3)/(3^6)+ ... + 2nC_n (2^n)/(3^(2n))+...</p>
<p>Where 4C_2 is 4 choose 2.</p>
<p>Any idea how to approach this problem?</p>
http://mathoverflow.net/questions/37253/trying-to-sum-a-series-related-to-catalan-numbers-perhaps/37254#37254Answer by Gjergji Zaimi for Trying to sum a series (related to catalan numbers perhaps)Gjergji Zaimi2010-08-31T11:56:44Z2010-08-31T11:56:44Z<p>The generating function of the <a href="http://en.wikipedia.org/wiki/Central_binomial_coefficient" rel="nofollow">central binomial coefficients</a> is
$$\sum_{n=0}^{\infty}\binom{2n}{n}x^n=\frac{1}{\sqrt{1-4x}}$$ and so the value of your series is 3.</p>
http://mathoverflow.net/questions/37253/trying-to-sum-a-series-related-to-catalan-numbers-perhaps/37255#37255Answer by Martin Rubey for Trying to sum a series (related to catalan numbers perhaps)Martin Rubey2010-08-31T12:04:23Z2010-08-31T12:04:23Z<p>edit: the preceding answer suggests that my browser didn't display the dots, i.e. you really meant the series, not the sequence... Sorry, the below doesn't answer the question.</p>
<hr>
<p>Does the following look right? (might this be homework?)</p>
<pre>
(1) -> f n == reduce(+, [binomial(2*i, i)*2^i/3^(2*i) for i in 0..n])
Type: Void
(2) -> guess([f n for n in 0..20], maxLevel==2)
Compiling function f with type NonNegativeInteger -> Fraction(
Integer)
s - 1
21 8p + 12
++-++ 20
4 | | ---------
| | 9p + 18
n - 1 p = 0 20
--+ 20
(2) [ > ------------------- + 1]
--+ 9
s = 0
21
Type: List(Expression(Integer))
(3) -> guessPRec [f n for n in 0..20]
(3)
[
[f(n): (9n + 18)f(n + 2) + (- 17n - 30)f(n + 1) + (8n + 12)f(n)= 0,
13
f(0)= 1, f(1)= --]
9
]
Type: List(Expression(Integer))
</pre>
<p>In general, it's often a good idea to generalise, i.e., introduce more parameters:</p>
<pre>
(4) -> f n == reduce(+, [binomial(2*i, i)*x^i/y^(2*i) for i in 0..n])
Compiled code for f has been cleared.
1 old definition(s) deleted for function or rule f
Type: Void
(5) -> guess([f n for n in 0..20], maxLevel==2)
Compiling function f with type NonNegativeInteger -> Fraction(
Polynomial(Integer))
s - 1
21 (4p + 6)x
++-++ 20
2x | | -----------
| | 2
n - 1 p = 0 (p + 2)y
--+ 20 20
(5) [ > ---------------------- + 1]
--+ 2
s = 0 y
21
Type: List(Expression(Integer))
(6) -> guessPRec [f n for n in 0..20]
(6)
[
[
f(n):
2 2
(n + 2)y f(n + 2) + ((- n - 2)y + (- 4n - 6)x)f(n + 1)
+
(4n + 6)x f(n)
=
0
,
2
y + 2x
f(0)= 1, f(1)= -------]
2
y
]
Type: List(Expression(Integer))
</pre>