Making D-modules on affine varieties more explicit - MathOverflow most recent 30 from http://mathoverflow.net 2013-06-19T13:09:12Z http://mathoverflow.net/feeds/question/3687 http://www.creativecommons.org/licenses/by-nc/2.5/rdf http://mathoverflow.net/questions/3687/making-d-modules-on-affine-varieties-more-explicit Making D-modules on affine varieties more explicit David Jordan 2009-11-01T18:00:47Z 2009-11-01T22:02:38Z <p>This is a follow up to my question <a href="http://mathoverflow.net/questions/2971/d-modules-supported-on-the-nilpotent-cone" rel="nofollow">about D-modules supported on the nilpotent cone</a>. I got some good answers there but now I have a more basic question.</p> <p>Consider an affine algebraic variety X, a closed subvariety i:Y-->X, and the intermediate extension of the structure sheaf on Y to all of X (do I denote this i<sub>!*</sub>O<sub>Y</sub> ? For that matter, explaining either the * or ! extension instead would be a helpful start if its easier).</p> <p>My question is this: Since X is affine, D(X) is just an associative algebra, generated by O(X) and Vect(X) by the usual construction. My question is how can I understand i<sub>!*</sub>O<sub>Y</sub> as a module the associative algebra D(X), supposing I understand D(X)?</p> <p>In other words, what is the vector space underlying i<sub>!*</sub>O<sub>Y</sub>, how do functions in O(X) and vector fields act?</p> <p>I probably need to invest some serious time with a textbook to answer this question myself, but any help getting started would be most appreciated!</p> http://mathoverflow.net/questions/3687/making-d-modules-on-affine-varieties-more-explicit/3689#3689 Answer by David Jordan for Making D-modules on affine varieties more explicit David Jordan 2009-11-01T19:00:05Z 2009-11-01T19:00:05Z <p>I think I can answer my subquestion about * extension after thinking about it, but it's really the ! and !* extensions I'd like to understand. I think I remember the * extension is just the pushforward.</p> <p>So i<sub>*</sub>O(Y) = O(X) &otimes;<sub>i</sub> O(Y), and the D-module action is always happening on the O(X) factor.</p> <p>Sorry to answer (a tiny part of) my own question, but I couldn't do it in a comment because of the formatting, and maybe this will save some kind respondent some time.</p> http://mathoverflow.net/questions/3687/making-d-modules-on-affine-varieties-more-explicit/3692#3692 Answer by Sam Lichtenstein for Making D-modules on affine varieties more explicit Sam Lichtenstein 2009-11-01T19:14:11Z 2009-11-01T19:14:11Z <p>Have you looked at Bernstein's <a href="http://www.math.uchicago.edu/~mitya/langlands/Bernstein/Bernstein-dmod.ps" rel="nofollow">lectures</a> on D-modules? He proves a result relevant to your questoin in Lec. 3, Sec. 14: for an affine embedding Y --> X with Y irreducible, if E is an O<sub>Y</sub>-coherent D<sub>Y</sub> module (i.e. a vector bundle with a flat connection) then the !* direct image from E can be characterized as the unique irreducible subquotient of either the * or ! direct image which has nonzero restriction to Y. Since it can be easy in such situations to compute the * direct image, this may be a good way to get a handle on the other functors too. For example, I think one can see from this that if we take the embedding of the origin into the affine line, then both the * and !* direct images of O<sub>Y</sub>=k (the ground field) are A(1)/A(1)t, where t is the coordinate on the affine line and A(1)=D<sub>X</sub> is the 1-dimensional Weyl algebra k[t,d/dt]. This quotient is rightly considered the "delta-function" A(1)-module, since its generator &delta; satisfies t&delta;=0. I'm not sure how similar to this case your general situation will be. But certainly by Kashiwara's theorem one knows that the * direct image (and hence the !* direct image) will be supported on the subvariety Y. </p> http://mathoverflow.net/questions/3687/making-d-modules-on-affine-varieties-more-explicit/3710#3710 Answer by David Treumann for Making D-modules on affine varieties more explicit David Treumann 2009-11-01T22:02:38Z 2009-11-01T22:02:38Z <p>Since Y is closed, the !, *, and !* extensions coincide, and there should be a straightforward (but confusing for me) way of doing what you want. If Y is smooth, then I wonder if you can identify the vector space you're talking about with something like sections of the conormal bundle to Y in X, but this is not quite right (e.g. when Y = X). When Y is singular, there is a more complicated story, having to do with the fact that the obvious definition of D-module on a singular variety is no good.</p> <p>When Y is only locally closed, describing the !* extension is a difficult problem. Vilonen's thesis, the only reference I know about this, is available here: </p> <p><a href="http://gdz.sub.uni-goettingen.de/en/dms/load/img/?PPN=PPN356556735_0081&amp;DMDID=dmdlog12" rel="nofollow">http://gdz.sub.uni-goettingen.de/en/dms/load/img/?PPN=PPN356556735_0081&amp;DMDID=dmdlog12</a></p> <p>There is even something nontrivial to say about the ! and * extensions--the characteristic cycles of such D-modules were computed by Schmid and Vilonen. Maybe there is a more elementary answer to your question about these extensions, though.</p>