backward and forward operators - MathOverflow most recent 30 from http://mathoverflow.net2013-05-23T09:12:06Zhttp://mathoverflow.net/feeds/question/33163http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/33163/backward-and-forward-operatorsbackward and forward operators Steven2010-07-24T02:27:49Z2010-07-24T02:27:49Z
<p>consider stochastic differential equation : $$d\xi(t)=b(t,\xi(t))dt+\sigma(t,\xi(t))dw$$ $t\in[s,T]$ and $\xi(s)=y$</p>
<p>where $w$ is a d-dimensional standard Brownian motion, $b\in \mathbb{R}^n$ and $\sigma\in \mathbb{R}^{n\times d}$.
The <em>backward operator</em> is defined to be
$$\frac{\partial}{\partial s}+A(s)=\frac{\partial}{\partial s}+\frac{1}{2}\sum_{i,j}a_{i,j}(s,y)\frac{\partial^2}{\partial y_i\partial y_j}+\sum_{i}b_{i}(s,y)\frac{\partial}{\partial y_i}$$</p>
<p>the <em>forward operator</em> is defined to be :</p>
<p>$$-\frac{\partial}{\partial s}+A^*(s)$$</p>
<p>where $$A^*(s)q:=\frac{1}{2}\sum_{i,j}\frac{\partial^2}{\partial y_i\partial y_j}[a_{i,j}(s,y)q]+\sum_{i}\frac{\partial}{\partial y_i}[b_{i}(s,y)q]$$</p>
<p>asumme that $P_{s,y}(\xi(t)\in B)=\int_{B}p(s,y,t,x)dx$ for all $B\in$ <strong><em>B</em></strong>$(\mathbb{R}^n)$ : the set of all Borel sets of $\mathbb{R}^n$</p>
<p>let $Q_{s,T}=(s,T)\times\mathbb{R}^{n}$ and $\phi\in C^{1,2}$ that has compact support in $Q_{s,T}$</p>
<p>CLAIM : $$ \int_{Q_{s,T}}[A(t)\phi] p dxdt=\int_{Q_{s,T}}\phi[ A^*(t)p]dxdt$$</p>
<p>so far I could showed that the above identity is true in case of 1-dimension, but not so satisfied with my argument. I am wondering that whether there is a neat way to see it? </p>
<p>Thanks for your time</p>