How much can we say about the number of nilpotents in a finite local commutative ring? - MathOverflow most recent 30 from http://mathoverflow.net2013-05-24T22:24:35Zhttp://mathoverflow.net/feeds/question/31463http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/31463/how-much-can-we-say-about-the-number-of-nilpotents-in-a-finite-local-commutativeHow much can we say about the number of nilpotents in a finite local commutative ring?Oliver2010-07-11T20:57:31Z2010-07-25T05:29:32Z
<p>A commutative ring is local if it has a single maximal ideal. If the ring is finite, this implies that all elements are either units or nilpotents. Further, all finite local rings have prime power order.</p>
<p>Given a prime power $p^k$ and a positive integer $n < p^k$, under what conditions on $p, k, n$ does there exist a local ring $R$ with $|R| = p^k$ and $n$ nilpotents?</p>