Analogue of a ring extension splitting in the Kummer case - MathOverflow most recent 30 from http://mathoverflow.net2013-05-18T14:35:28Zhttp://mathoverflow.net/feeds/question/29156http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/29156/analogue-of-a-ring-extension-splitting-in-the-kummer-caseAnalogue of a ring extension splitting in the Kummer caseAlexandra Seceleanu2010-06-22T22:10:08Z2010-06-22T22:10:08Z
<blockquote>
<p>Background (the Kummer extension case)</p>
</blockquote>
<p>Let $R$ be a complete regular local ring (it follws that it's a UFD) with a prime integer $p$ contained in the maximal ideal of $R$ (I'm mostly interested in $R=V[[x_1\ldots x_n]]$ with V a DVR). Consider a finite extension of rings $R\hookrightarrow A$ with $A = R[u^{\frac{1}{p}}]$.</p>
<p>Let $K$ and $F$ be the fraction fields of $R$ and $A$ respectively. Let $\xi$ be a $p^{th}$ primitive root of 1 and consider the following commutative diagrams where horizontally displayed extensions are of order $p-1$ and vertical ones are of order $p$.</p>
<p><code>$\begin{array}{ccc}
K & \hookrightarrow & K[\xi]\\
\downarrow & & \downarrow \\
L &\hookrightarrow & L[\xi]\\
\end{array}$</code>
where $K[\xi]\subset L[\xi]$ is a Kummer extension with $Gal((L[\xi]/K[\xi])=<\sigma>\simeq \mathbf{Z}/p\mathbf{Z}$ </p>
<p><code>$\begin{array}{ccc}
R & \hookrightarrow & R' \\
\downarrow & & \downarrow \\
A &\hookrightarrow & A' \\
\end{array}$</code>
where $R'$ is the integral closure of $R$ in $R[\xi]$ and $A'$ is the integral closure of $A$ in $L[\xi]$.</p>
<p>Now $L[\xi]$ has an eigenspace decomposition $L[\xi]=L_1\bigoplus \ldots \bigoplus L_{p} $, where <code>$L_i= \{ x \in L[\xi]| \sigma(x)=\xi^i *x \}$</code>. </p>
<p>Here the contractions $S_i=A'\cap L_i$ are rank one $R'$-modules (in fact <code>$ S_i= \{x \in A' |\sigma(x)=\xi^i*x\}$</code>).</p>
<blockquote>
<p>Question</p>
</blockquote>
<p>Suppose that we DROP the hypothesis $A = R[u^{\frac{1}{p}}]$ and only assume $[L:K]=p$. Let $L'$ be such that $L'/K$ is Galois and consider the analogous diagrams
<code>$\begin{array}{ccc}
K & \hookrightarrow & K'\\
\downarrow & & \downarrow \\
L &\hookrightarrow & L'\\
\end{array}$</code> and
<code>$\begin{array}{ccc}
R & \hookrightarrow & R'\\
\downarrow & & \downarrow \\
A &\hookrightarrow & A'\\
\end{array}$</code>.</p>
<p>$L'$ still has an eigenspace decomposition of the type $L'=L_1\bigoplus \ldots \bigoplus L_{p} $, where $L_i\simeq L$. </p>
<blockquote>
<p>What conditions would ensure that the contractions $S_i=L_i\cap A'$ are still rank one $R'$-modules? </p>
</blockquote>
<p>I am guessing that we need $[L':L]$ not to be divisible by $p$, but would be happy to see a proof even under more restrictive conditions (such as $Gal(L'/L)$ commutes with $Gal(L'/R')$ perhaps). </p>
<p>Any help is much appreciated.</p>