Elementary proof wanted: every local principal ideal ring is a quotient of a PID - MathOverflow most recent 30 from http://mathoverflow.net2013-05-21T22:53:58Zhttp://mathoverflow.net/feeds/question/25663http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/25663/elementary-proof-wanted-every-local-principal-ideal-ring-is-a-quotient-of-a-pidElementary proof wanted: every local principal ideal ring is a quotient of a PIDPete L. Clark2010-05-23T13:45:13Z2012-06-18T05:43:12Z
<p>I am looking for a more elementary proof of the following result:</p>
<p>Theorem (Hungerford, 1968): Let $R$ be a principal ideal ring. Then $R \cong \prod_{i=1}^n R_i$, where each $R_i$ is a homomorphic image of a principal ideal <em>domain</em> (PID).</p>
<p>Hungerford's article is available free online at:</p>
<p><a href="http://projecteuclid.org/euclid.pjm/1102986148" rel="nofollow">http://projecteuclid.org/euclid.pjm/1102986148</a></p>
<p>What do I mean by "more elementary"? Hungerford uses the Cohen structure theory of complete local rings, which I would like to avoid (because I have notes on commutative algebra which do not discuss such things). </p>
<p>Note that Hungerford's theorem is a refinement of a previous result of Zariski and Samuel,
which asserts that a principal ideal ring is isomorphic to a finite direct product of rings, each of which is either a PID or a "special principal ideal ring", i.e., a local Artinian principal ideal ring. The proof of this result uses primary decomposition, which is acceptable to me (in fact I put a section on primary decomposition into my notes for exactly this application). </p>
<p>Given the theorem of Zariski-Samuel, Hungerford's result is plainly equivalent to the fact that every Artinian local principal ideal ring is the quotient of a PID. Now doesn't that sound like you should be able to prove it without invoking the structure theory of complete local rings? </p>
http://mathoverflow.net/questions/25663/elementary-proof-wanted-every-local-principal-ideal-ring-is-a-quotient-of-a-pid/99872#99872Answer by NN for Elementary proof wanted: every local principal ideal ring is a quotient of a PIDNN2012-06-18T05:43:12Z2012-06-18T05:43:12Z<p>Theorem 5.2 in <a href="http://www.emis.de/journals/BAG/vol.46/no.1/b46h1her.pdf" rel="nofollow">http://www.emis.de/journals/BAG/vol.46/no.1/b46h1her.pdf</a> gives an answer
(take the projective limit. The paper has a related one with corrections,
but not for the part that is related to your question). This is for a non-commutative
case, and the theorem has a non-commutative extension: a PIR is a finite direct product
of prime and artinian indecomposable cases, which are matrix rings over CPU rings
(Faith, Algebra II should contain all the needed references)</p>