What does the disjunction elimination rule say? - MathOverflow most recent 30 from http://mathoverflow.net 2013-05-26T08:49:38Z http://mathoverflow.net/feeds/question/16494 http://www.creativecommons.org/licenses/by-nc/2.5/rdf http://mathoverflow.net/questions/16494/what-does-the-disjunction-elimination-rule-say What does the disjunction elimination rule say? Francesco Turco 2010-02-26T09:55:17Z 2011-05-12T16:56:48Z <p>I read about two different versions of the disjunction elimination rule.</p> <p>The first version (<a href="http://www.fecundity.com/logic/" rel="nofollow">http://www.fecundity.com/logic/</a>) says that:</p> <ul> <li>if $\Sigma\vdash\phi_0\lor\phi_1$ and $\Sigma\vdash\lnot\phi_0$, then $\Sigma\vdash\phi_1$</li> <li>if $\Sigma\vdash\phi_0\lor\phi_1$ and $\Sigma\vdash\lnot\phi_1$, then $\Sigma\vdash\phi_0$</li> </ul> <p>The second version (S. Hedman - A First Course in Logic) says that:</p> <ul> <li>if $\Sigma\models\phi_0\lor\phi_1$, $\Sigma\cup\left\{\phi_0\right\}\vdash\phi_2$ and $\Sigma\cup\left\{\phi_1\right\}\vdash\phi_2$, then $\Sigma\vdash\phi_2$</li> </ul> <p>Using the first version of the rule, I can't even demonstrate that if $\Sigma\vdash\phi\lor\phi$ then $\Sigma\vdash\phi$. Perhaps the entire system presented by the first source is not complete, in the sense that you can't prove certain true statements. Of course, it may be my fault, instead.</p> <p>Thanks.</p> http://mathoverflow.net/questions/16494/what-does-the-disjunction-elimination-rule-say/16497#16497 Answer by Neel Krishnaswami for What does the disjunction elimination rule say? Neel Krishnaswami 2010-02-26T10:09:04Z 2010-02-26T10:09:04Z <p>Yes, the first version of your rule is incomplete. In natural deduction style, the elimination rule for disjunctions is: </p> <p>$$\frac{\Gamma \vdash A \vee B \qquad \Gamma, A\vdash C \qquad \Gamma, B\vdash C}{\Gamma \vdash C}$$</p> <p>This corresponds to the second version of your rule. </p> http://mathoverflow.net/questions/16494/what-does-the-disjunction-elimination-rule-say/16528#16528 Answer by Charles Stewart for What does the disjunction elimination rule say? Charles Stewart 2010-02-26T16:45:40Z 2010-02-26T16:45:40Z <p>The first rule is not the regular disjunction elimination rule, but is known as <a href="http://en.wikipedia.org/wiki/Disjunctive_syllogism" rel="nofollow">disjunctive syllogism</a>, and is essentially the modus tollendo ponens rule of term logic. The two rules are mutually admissible in reasonable formulations of classical logic, but the first rule is strictly weaker in intuitionistic logic.</p>