most recent 30 from http://mathoverflow.net 2013-05-25T08:47:36Z http://mathoverflow.net/feeds/question/1523 http://www.creativecommons.org/licenses/by-nc/2.5/rdf http://mathoverflow.net/questions/1523/universal-covers-of-domains-in-complex-projective-space engelbrekt 2009-10-20T23:35:17Z 2009-10-21T01:25:30Z

<p>The Uniformization Theorem states that the universal cover of a Riemann surface is biholomorphic to the extended complex plane, the complex plane or the open unit disk. Each of these three is a domain in the extended complex plane. In particular, then, the universal cover of a domain in the extended complex plane is biholomorphic to a domain in the extended complex plane. This leads to an analogous question in higher dimensions: Is the universal cover of a domain in complex projective space biholomorphic to a domain in complex projective space? More precisely, I am asking for a counterexample. Many results in one complex variable break in several complex variables, and the Uniformization Theorem is fairly delicate, so it seems reasonable to expect it to break. Perhaps there is a counterexample that one can see just by topology?</p>

http://mathoverflow.net/questions/1523/universal-covers-of-domains-in-complex-projective-space/1544#1544 jvp 2009-10-21T01:25:30Z 2009-10-21T01:25:30Z

<p>Consider a tubular neighborhood of three generic lines on P^2. The fundamental group is Z. The universal covering will contain an infinite chain of P^1's, and in particular two disjoint P^1's. Thus it cannot be a domain in P^2.</p>