Closed form of a nonlinear recurrence sequence. - MathOverflow most recent 30 from http://mathoverflow.net2013-05-23T09:47:05Zhttp://mathoverflow.net/feeds/question/12484http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/12484/closed-form-of-a-nonlinear-recurrence-sequenceClosed form of a nonlinear recurrence sequence.Jason Knight2010-01-21T02:26:43Z2010-01-21T14:02:48Z
<p>The master theorem seems to fail on nonlinear recursive functions. Is there a standard tool for finding the closed forms of recursive functions of this form?</p>
<p>The question comes from trying to find the closed form of the following recursive function:
$f_i(X) = (f_{i-1}(X)^2 + f_{i-1}(X))/2$<br>
Where:<br>
$f_0(X) = X$</p>
<p>I would be willing to part with recurrence relations for this function, but I would be much more delighted to learn a general method or trick which makes finding closed forms of functions like this simple.</p>
http://mathoverflow.net/questions/12484/closed-form-of-a-nonlinear-recurrence-sequence/12541#12541Answer by Julián Aguirre for Closed form of a nonlinear recurrence sequence.Julián Aguirre2010-01-21T14:02:48Z2010-01-21T14:02:48Z<p>As has already been explained, there is no hope in general of finding explicit solutions to nonlinear recurrences. However, for your example, it is possible to find $\lim_{n\to\infty}f_n(X)$ for all real $X$.</p>
<p>The function $g(x)=(x^2+x)/2$ has two fixed points: $x=0$ (atractor) and $x=1$ (repulsor). Its respective stable sets are $(-2,1)$ and $\{-2,1\}$; $(-\infty,-2)\cup(1,+\infty)$ is the stable set of $+\infty$. Thus,</p>
<p>$$\lim_{n\to\infty}f_n(X)=\left\{\matrix{0, & X\in(-2,1)\cr 1, & X\in\{-2,1\}\cr +\infty, & X\in(-\infty,-2)\cup(1,+\infty)}\right.$$</p>