On the location of zeros of L functions from modular forms - MathOverflow most recent 30 from http://mathoverflow.net 2013-05-24T01:53:05Z http://mathoverflow.net/feeds/question/118873 http://www.creativecommons.org/licenses/by-nc/2.5/rdf http://mathoverflow.net/questions/118873/on-the-location-of-zeros-of-l-functions-from-modular-forms On the location of zeros of L functions from modular forms GM 2013-01-14T13:31:08Z 2013-01-14T15:11:19Z <p>I understand that the Mellin transform of a modular form is expected to satisfy RH when it is an eigenform of all Hecke operators, in which case it has an Euler product. Now about when the form is not an eigenform: Is it known a case where the zeros are all in the critical strip?</p> http://mathoverflow.net/questions/118873/on-the-location-of-zeros-of-l-functions-from-modular-forms/118881#118881 Answer by Marc Palm for On the location of zeros of L functions from modular forms Marc Palm 2013-01-14T14:53:25Z 2013-01-14T15:11:19Z <p>Perhaps I don't understand the question, but in its current form the answer is no.</p> <p>A general modular form of fixed weight will be a linear combination of Hecke eigenforms of that weight. The Gamma factors will imply that there are trivial zeros outside the critical stripe.</p> <p>But I guess you have an L-function with symmetric functional equation in mind? The Mellin transform is a linear operator, so the result is a linear combination of Hecke L functions times a Gamma factors. Assuming that you find some combination non-vanishing out the complement of closure of the critical stripe via some estimates I don't know, you will need a good argument for non-vanishing on the boundary of the critical stripe, where the function is expected to be universal. </p> <p>What is the motivation for the question?</p> http://mathoverflow.net/questions/118873/on-the-location-of-zeros-of-l-functions-from-modular-forms/118883#118883 Answer by Johan Andersson for On the location of zeros of L functions from modular forms Johan Andersson 2013-01-14T15:01:49Z 2013-01-14T15:01:49Z <p>When it is not a Hecke-Eigen form, the Hecke L-series connected with the modular form does not have an Euler product. However it can still be written as a linear combination of Hecke L-series that have Euler-products. Thus the situation will resemble the case of linear combinations of Dirichlet L-series. In particular we can use joint Voronin universality to obtain $\gg T$ zeroes in any strip $1/2&lt;\sigma_1&lt;\Re(s)&lt;\sigma_2 &lt; 1$, $-T &lt; \Im(s)&lt; T.$ These results follows from the analytic properties of the Rankin-Selberg zeta-function (which gives "independence results" for Hecke eigenvalues of primes attached to different cusp forms). You should be able to find results of this kind in Steuding's SLN "Value Distribution of L-functions".</p> <p>Also the results of Davenport-Heilbronn for the Hurwitz zeta-function can be proved, i.e. For any $\epsilon>0$ there exists $\gg T$ zeroes with $1&lt;\Re(s)&lt;1+\epsilon$ and $-T &lt; \Im(s) &lt; T$.</p> <p>Stronger results corresponding to results of Karatsuba, Bombieri, Hejhal and Selberg for Dirichlet L-function that holds close to the critical line likely also holds. I think the russian school (Irina Rezvyakova) has proved results in this direction.</p>