Hodge-Tate weights of etale cohomology - MathOverflow most recent 30 from http://mathoverflow.net2013-05-22T14:27:20Zhttp://mathoverflow.net/feeds/question/117721http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/117721/hodge-tate-weights-of-etale-cohomologyHodge-Tate weights of etale cohomologynatura2012-12-31T12:25:49Z2012-12-31T12:52:07Z
<p>Let $K/\mathbb Q_p$ be a local field, $X/K$ a proper scheme with semi-stable reduction. </p>
<p><strong>Question</strong>: What is the possible range of Hodge-Tate weights of the etale cohomology $H^i(X_{\overline K}, \mathbb Q_p)$ as a $G_K$ representation?</p>
<p>The only "understanding" that I have is that when $i=1$, things reduce to abelian schemes. And the Hodge-Tate weights are all in {0,1}. Is that right?</p>
<p>What will happen with $i \geq 2$? Will the range be between 0 and $i$? It is true for abelian schemes right? Since $H^i$ in this case is the $i$-th wedge product of $H^1$.</p>
http://mathoverflow.net/questions/117721/hodge-tate-weights-of-etale-cohomology/117725#117725Answer by wccanard for Hodge-Tate weights of etale cohomologywccanard2012-12-31T12:52:07Z2012-12-31T12:52:07Z<p>The Hodge-Tate weights are just the numbers where the filtration in the de Rham cohomology jumps, so as you suspected will be in the range $[0,i]$. To prove this I guess one needs to observe, amongst other things, that the associated graded ring of $B_{dR}$ is $B_{HT}$, and that there's a comparison theorem relating de Rham and etale cohomology, with the field of periods being $B_{dR}$. It's all downhill from there.</p>