Direct product of rings - MathOverflow most recent 30 from http://mathoverflow.net2013-05-23T06:45:40Zhttp://mathoverflow.net/feeds/question/117486http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/117486/direct-product-of-ringsDirect product of rings chatish2012-12-29T07:52:19Z2013-01-09T14:26:47Z
<p>Is there an infinite family $\lbrace R_\alpha\rbrace_\alpha $ of rings (with identity $1\neq 0$) such that
their direct product is a (semi) hereditary ring ?</p>
<p>I think the answer must be negative but i have no proof or counterexample yet. </p>
http://mathoverflow.net/questions/117486/direct-product-of-rings/117564#117564Answer by Fred Rohrer for Direct product of rings Fred Rohrer2012-12-29T21:30:55Z2012-12-29T22:15:03Z<p>Products of fields are semihereditary. This follows from the facts that products of fields are von Neumann regular and that von Neumann regular rings are semihereditary. A proof can be found (as suggested by David White) in Lam's <em>Lectures on modules and rings,</em> Example 2.32 d).</p>
<p>(In the above, fields and rings are not necessarily commutative.)</p>