slice-ribbon for links (surely it's wrong) - MathOverflow most recent 30 from http://mathoverflow.net2013-05-25T11:29:56Zhttp://mathoverflow.net/feeds/question/11713http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/11713/slice-ribbon-for-links-surely-its-wrongslice-ribbon for links (surely it's wrong)Ryan Budney2010-01-14T01:13:55Z2010-04-08T14:21:51Z
<p>The slice-ribbon conjecture asserts that all slice knots are ribbon. </p>
<p>This assumes the context: </p>
<p>1) A `knot' is a smooth embedding $S^1 \to S^3$. We're thinking of the 3-sphere as the boundary of the 4-ball $S^3 = \partial D^4$. </p>
<p>2) A knot being slice means that it's the boundary of a 2-disc smoothly embedded in $D^4$. </p>
<p>3) A slice disc being ribbon is a more fussy definition -- a slice disc is in ribbon position if the distance function $d(p) = |p|^2$ is Morse on the slice disc and having no local maxima. A slice knot is a ribbon knot if one of its slice discs has a ribbon position.</p>
<p>My question is this. All the above definitions have natural generalizations to links in $S^3$. You can talk about a link being slice if it's the boundary of disjointly embedded discs in $D^4$. Similarly, the above ribbon definition makes sense for slice links. Are there simple examples of $n$-component links with $n \geq 2$ that are slice but not ribbon? Presumably this question has been investigated in the literature, but I haven't come across it. Standard references like Kawauchi don't mention this problem (as far as I can tell). </p>
http://mathoverflow.net/questions/11713/slice-ribbon-for-links-surely-its-wrong/12325#12325Answer by czy for slice-ribbon for links (surely it's wrong)czy2010-01-19T17:56:39Z2010-01-19T17:56:39Z<p>As far as I know, extension of slice and ribbon to links is not unique.
There are "strong slice", "weak slice", "strong ribbon" and "weak ribbon" for links.</p>
<p>"CHARACTERIZATION OF SLICES AND RIBBONS" (by H.FOX) mentioned these concepts. </p>
http://mathoverflow.net/questions/11713/slice-ribbon-for-links-surely-its-wrong/18971#18971Answer by Peter Teichner for slice-ribbon for links (surely it's wrong)Peter Teichner2010-03-22T01:38:51Z2010-03-22T01:38:51Z<p>Ryan, I think this is an open problem. The best related result I know is a theorem of Casson and Gordon [A loop theorem for duality spaces and fibred ribbon knots. Invent. Math. 74 (1983)] saying that for a fibred knot that bounds a homotopically ribbon disk in the 4-ball, the slice complement is also fibred. </p>
<p>More precisely, they are assuming that the knot K bounds a disk R in the 4-ball such that the inclusion </p>
<p>$S^3 \smallsetminus K \hookrightarrow D^4 \smallsetminus R$ </p>
<p>induces an epimorphism on fundamental groups. If one glues R to a fibre of the fibration $S^3 \smallsetminus K \to S^1$ to obtain a closed surface F, then the statement is that the monodromy extends from F to a solid handlebody which is a fibre of a fibration $D^4 \smallsetminus R \to S^1$ extending the given one on the boundary.</p>