Extending arithmetic functions (and associated Dirichlet series) to arbitrary rings of integers - MathOverflow most recent 30 from http://mathoverflow.net2013-05-25T17:34:31Zhttp://mathoverflow.net/feeds/question/108796http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/108796/extending-arithmetic-functions-and-associated-dirichlet-series-to-arbitrary-rinExtending arithmetic functions (and associated Dirichlet series) to arbitrary rings of integersSteve Pandarus2012-10-04T09:41:14Z2012-10-04T11:24:23Z
<p>Many classical arithmetic functions can be thought of as functions on the set of (non-zero) ideals of $\mathbb{Z}$ rather than as functions on $\mathbb{N}$.</p>
<p>Example: For $n \in \mathbb{N}$ the divisor function $d(n)$ is defined to equal the number of divisors of $n$. Equivalently, we could define $d(I)$ to the number of ideals dividing the ideal $I \lhd \mathbb{Z}$, where we count once the fact that $(1)|(n)$.</p>
<p>Now, the associated Dirichlet could be written as
$$
\sum^\infty_{n=1} d(n) n^{-s} = \sum_{I \lhd \mathbb{Z}} d(I) N(I)^{-s} = \zeta(s)^2.
$$</p>
<p>If $K$ is a number field with ring of integers $\mathcal{O}$ we can extend the definition of $d(I)$ to the ideals of $\mathcal{O}$. Furthermore, we can consider the associated Dirichlet series:
$$
\sum_{I \lhd \mathcal{O}} d(I) N(I)^{-s}.
$$</p>
<p>QUESTIONS: Is this Dirichlet series equal to $\zeta_K(s)^2$, the square of the Dedekind zeta function of the field? </p>
<p>Does this phenomena generalize? ie if $a(n)$ is arithmetic function that can be equivalently defined on the ideals of $\mathbb{Z}$ and the Dirichlet series associated to $a(n)$ is a quotient of Riemann zeta functions (= Dedekind zeta function of $\mathbb{Q}$). Can we simply `replace' the Riemann zeta functions with the appropriate Dedekind zeta functions to obtain the Dirichet series associated to the extended a(n)? </p>
http://mathoverflow.net/questions/108796/extending-arithmetic-functions-and-associated-dirichlet-series-to-arbitrary-rin/108806#108806Answer by David Loeffler for Extending arithmetic functions (and associated Dirichlet series) to arbitrary rings of integersDavid Loeffler2012-10-04T11:24:23Z2012-10-04T11:24:23Z<p>The answer to your Question 1 is "yes". It's clear that the number of ideals of $\mathcal{O}$ of norm $\le M$ is bounded above by a polynomial in $M$, so one can manipulate Dirichlet series term-by-term for $Re(s) \gg 0$ and argue that</p>
<p><code>$$ \zeta_K(s)^2 = \sum_{A, B} N(A)^{-s} N(B)^{-s} = \sum_{C} \#\{ (A, B) : AB = C\} N(C)^{-s} = \sum_C d(C) N(C)^{-s}.$$</code></p>
<p>As for Question 2 it's not entirely clear to me what your precise question is, but philosophically at least the answer is "yes" -- any arithmetical function $a$ definable purely in terms of ideals of $\mathbb{Z}$ will have a natural generalization to ideals of a number field, and if you can express $\sum_n a(n) n^{-s}$ in terms of the Riemann zeta then the same argument should give you an expression for $\sum_{I \triangleleft \mathcal{O}} a(I) N(I)^{-s}$ in terms of $\zeta_K(s)$. </p>