Additive functors preserving quasi-isomorphism - MathOverflow most recent 30 from http://mathoverflow.net2013-05-24T13:17:25Zhttp://mathoverflow.net/feeds/question/108670http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/108670/additive-functors-preserving-quasi-isomorphismAdditive functors preserving quasi-isomorphismLMN2012-10-02T21:55:31Z2012-10-02T23:18:38Z
<p>Let $F: \mathcal{A} \rightarrow \mathcal{B}$ be an additive functor between abelian categories (with enough injectives and projectives) and $K^\cdot, L^\cdot$ objects of $\textrm{Ch}(\mathcal{A})$. Suppose $F$ is left (resp. right) exact. Then $F$ preserves quasi-isomorphisms between complexes $f: K^\cdot \rightarrow L^\cdot$ of objects acyclic for $F$. Since $\textrm{Cyl}(f)$ is quasi-isomorphic to $L^\cdot$ and the objects of $\textrm{Cone}(f)$ are a direct sum of those in $L^\cdot, K^\cdot$, this follows by applying $F$ to the short exact sequence </p>
<p>$0 \rightarrow K^\cdot \rightarrow \textrm{Cyl}(f) \rightarrow \textrm{Cone}(f) \rightarrow 0$ (p. 155, Gelfand-Manin).</p>
<p>Is the same true in more generality? I know that only exact functors preserve arbitrary quasi-isomorphisms, but do left (resp. right) exact additive functors preserve lots of other quasi-isomorphisms? (Feel free to impose boundedness conditions on the relevant complexes $K^\cdot, L^\cdot$ and any reasonable conditions on $\mathcal{A}, \mathcal{B}$).</p>