Why would dim primitive irrep divide size of some conjugacy class ? - MathOverflow most recent 30 from http://mathoverflow.net2013-06-20T01:13:39Zhttp://mathoverflow.net/feeds/question/108406http://www.creativecommons.org/licenses/by-nc/2.5/rdfhttp://mathoverflow.net/questions/108406/why-would-dim-primitive-irrep-divide-size-of-some-conjugacy-classWhy would dim primitive irrep divide size of some conjugacy class ? Alexander Chervov2012-09-29T13:07:13Z2012-09-29T13:28:01Z
<p>From <a href="http://www.uv.es/amoquin/35.pdf" rel="nofollow">Isaacs et.al. 2005</a></p>
<blockquote>
<p>Conjecture C. Let χ be a primitive
irreducible character of an arbitrary
finite group G. Then χ(1) divides |
clG(g)| for some element g ∈ G.</p>
<p>Here, of course, we have written
clG(g) to denote the class of g in G.
We have checked that Conjecture C
holds for all irreducible characters
(primitive or not) of all groups in
the Atlas <a href="http://www.uv.es/amoquin/35.pdf" rel="nofollow">1</a>.</p>
</blockquote>
<p><strong>Question 1</strong> What is motivation for this ? Is it possible to describe what
conjugacy class(es) should correspond to irreducible representation in this way ?
(at least for some standard groups S_n, A_n, GL_n(F_q),...) What are representative examples? </p>
<p><strong>Question 2</strong> Is it still open ? </p>
<hr>
<p>The authors write:</p>
<blockquote>
<p>We now digress to explain our original
motivation for considering these
questions. There are numerous
parallels and analogies between
theorems concerning the of set
irreducible character degrees of a
finite group and theorems concerning
the set of conjugacy class sizes of
such groups. This suggests that
perhaps there are some subtle
arithmetic connections between these
two sets of integers associated with a
given group. One such connection that
is easy to see is that each prime
number that divides an irreducible
character degree of G must also divide
some class size of G. If G is
solvable, then S. Dolfi showed that
more is true. He proved [2] that given
any two distinct primes p and q such
that pq divides some irreducible
character degree of a solvable group
G, then pq also divides some class
size of G. One might conjecture that
the analogous assertion for three or
more distinct primes is also true, but
as far as we know, this remains open.</p>
</blockquote>
<hr>
<p><strong>Partial result:</strong></p>
<p>In the following, we use the notation np to denote the p-part of a positive
integer n, where p is a prime number.</p>
<p>Corollary D. Let χ be a primitive irreducible character of a solvable group
G, and let p be a prime divisor of |G|. Then χ(1)p divides (| clG(g)|p)
3 for some element g ∈ G.</p>
<hr>
<p>Not related results, for complteness:</p>
<p>Denote CV(g) fixed point subspace for g in V.</p>
<p>Our main result is the following.</p>
<p>Theorem A. Let V be a nonzero finite dimensional completely reducible
F G-module, where F is any field and G is any finite group. Assume that
CV (G) = 0 and let p be the smallest prime divisor of |G|. Then there exists
some element g ∈ G such that</p>
<p>$ dim CV (g) ≤ (1/p) ~ dim V $.</p>
<p>The fraction 1/p cannot, in general, be replaced by any smaller quantity.
In particular, this shows that Neumann’s conjecture is valid for odd-order
groups, at least...</p>
<p>Corollary B. Let V be a nonzero finite dimensional completely reducible
F G-module, where F is an arbitrary field and G is any finite group, and
assume that CV (G) = 0. Then</p>
<p>$1/ |G| \sum_{g∈G} dim CV (g) ≤ ((p + 1)/ 2p)~~ dim V$ ,</p>
<p>where p is the smallest prime divisor of |G|.</p>